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To find the smallest possible value of 20P + 10Q + R when P, Q, and R are different positive integers, we should start by assigning the smallest possible values to P, Q, and R. Since they are different positive integers, we can assign P = 1, Q = 2, and R = 3. Substituting these values into the expression, we get 20(1) + 10(2) + 3 = 20 + 20 + 3 = 43. Therefore, the smallest possible value of 20P + 10Q + R is 43.
It equals the value of 'q', multiplied by itself.
1750 2 x 5p x q where p and q are prime numbers. 2 * 5^p * q where p = 3 and q = 7
q-1
q=-6