it's only divisible by 3
243 divided by 3 is 81
No, 243 is not divisible by 5. A number is divisible by 5 if it ends in 0 or 5, and since 243 ends in 3, it does not meet that criterion.
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.
535 is not divisible by 2, 3, 9, or 10. It is an odd number, so it cannot be divisible by 2. The sum of its digits (5 + 3 + 5 = 13) is not divisible by 3, and it does not end in 0 or 5, which means it is not divisible by 10. However, 535 is divisible by 5, as it ends with a 5.
30 is divisible by, and is the least common multiple of, 2, 3, and 5.
No, 243 is not divisible by 5. A number is divisible by 5 if it ends in 0 or 5, and since 243 ends in 3, it does not meet that criterion.
yep it is because 2 is divisible by 2 and 3 is divisible by 3 and 0 is divisible by 5 have fun suckers!
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.
535 is not divisible by 2, 3, 9, or 10. It is an odd number, so it cannot be divisible by 2. The sum of its digits (5 + 3 + 5 = 13) is not divisible by 3, and it does not end in 0 or 5, which means it is not divisible by 10. However, 535 is divisible by 5, as it ends with a 5.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.
30 is divisible by, and is the least common multiple of, 2, 3, and 5.
One of the infinitely many integers divisible by 2, 3 and 5 is 3000.
It is divisible by 2, 5 and 10, but not 3 and 9.
2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.