Q: Is 252 divisible by both 2 and 5?

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No.

10 is divisible by both 5 and 2, as are any multiples of 10.

No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.

10, 20, 30, 40, and so on. In other words, any multiple of ten (and only multiples of ten) are divisible by both 2 and 5.

Your question is impossible to answer. Any number that is divisible by both 2 and 5 will also be divisible by 10. 30 and 60 are not divisible by 9.

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No.

Not without a remainder. Only numbers that end in 5 or 0 are evenly divisible by 5. 252 / 5 = 50.4

10 is divisible by both 5 and 2, as are any multiples of 10.

Because 10 is divisible by both 2 and 5

No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.

A number divisible by both 2 and 5 will be divisible by their product (2 x 5), which is 10. Any number divisible by 10 ends in 0. The only number listed that ends in 0 is 110.

Yes

Both are divisible by 5.

There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.

10, 20, 30, 40, and so on. In other words, any multiple of ten (and only multiples of ten) are divisible by both 2 and 5.

Your question is impossible to answer. Any number that is divisible by both 2 and 5 will also be divisible by 10. 30 and 60 are not divisible by 9.

No