There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
No
10
Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.
Both the top and bottom are divisible by 2. The answer, then, is 2/5.
10 is divisible by both 5 and 2, as are any multiples of 10.
Because 10 is divisible by both 2 and 5
No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.
A number divisible by both 2 and 5 will be divisible by their product (2 x 5), which is 10. Any number divisible by 10 ends in 0. The only number listed that ends in 0 is 110.
Yes
Both are divisible by 5.
There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
10, 20, 30, 40, and so on. In other words, any multiple of ten (and only multiples of ten) are divisible by both 2 and 5.
Your question is impossible to answer. Any number that is divisible by both 2 and 5 will also be divisible by 10. 30 and 60 are not divisible by 9.
No
10
No. The smallest number divisible by both 5 and 2 is their lowest common Multiple (LCM) which is 10; ALL multiples of their LCM are divisible by 5 and 2, ie 10, 20, 30, 40, 50, ... are all divisible by 5 and 2.