Yes
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There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
10
No
Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.
Multiples of both 2 and 5 are numbers that are divisible by both 2 and 5 without leaving a remainder. To find these multiples, you can simply find the common multiples of 2 and 5. The least common multiple of 2 and 5 is the smallest number that is divisible by both 2 and 5, which is 10. Therefore, multiples of both 2 and 5 include 10, 20, 30, 40, and so on.