No.
To calculate the diagonal, use the Pythagorean Theorem.6^2 + 6^2 = x^236 + 36 = x^272 = x^2sqrt72 = xx = 8.485.....
If the sides of a right angle triangle are 6 feet and 8 feet then by using Pythagoras' theorem the hypotenuse will be 10 feet
The important thing here is that it's a right triangle. Since it is, you can use the Pythagorean theorem. The Pythagorean theorem is as follows... (Length of leg)^2 + (Length of leg)^2 = (Hypotenuse)^2 6^2 + 8^2 = h^2 36 + 64 + h^2 100 = h^2 (Now extract the root from both sides) 10=h
Pythagorean Theorem a^2 + b^2 = c^2 where c is the hypotenuse c =sqrt(6^2 + 8^2) c = sqrt(100) = 10
There are 19 various aspects of Pythagoras theorem. Pythagorean Theorem (1) Pythagoras Theorem(2) Pythagorean Theorem (3) Pythagorean Theorem (4) Pythagoras Theorem(5) Pythagorean Theorem(6) Pythagrean Theorem(7) Pythagoras Theorem(8) Pythagorean Theorem (9) Hyppocrates' lunar Minimum Distance Shortest Distance Quadrangular Pyramid (1) Quadrangular Pyramid (2) Origami Two Poles Pythagoras Tree(1) Pythagoras Tree(2) Theorem by Pappus
Find this using the Pythagorean theorem (a=(1/2 * 8) b=the altitude c = 6).
No.
To calculate the diagonal, use the Pythagorean Theorem.6^2 + 6^2 = x^236 + 36 = x^272 = x^2sqrt72 = xx = 8.485.....
6^2+8^2 = 36+64 = 100 9^2 = 81 100>81 This triangle is not a right angle triangle
If the sides of a right angle triangle are 6 feet and 8 feet then by using Pythagoras' theorem the hypotenuse will be 10 feet
The important thing here is that it's a right triangle. Since it is, you can use the Pythagorean theorem. The Pythagorean theorem is as follows... (Length of leg)^2 + (Length of leg)^2 = (Hypotenuse)^2 6^2 + 8^2 = h^2 36 + 64 + h^2 100 = h^2 (Now extract the root from both sides) 10=h
The Pythagorean theorem says; a^2 + b^2 = c^2 a = 6 b = 6 c = 10 6^2 + 8^2 = 100 could be a right triangle
if you know the height and the apothem, use pythagorean theorem to solve for it.
6 * sqrt(3) cm. This should be trivially obvious from the Pythagorean theorem.
Pythagorean Theorem a^2 + b^2 = c^2 where c is the hypotenuse c =sqrt(6^2 + 8^2) c = sqrt(100) = 10
Perimeter: 4 times square root of (3.5^2+6^2) = 2 times square root of 193 in cm