A "Pythagorean triple" is a set of 3 numbers that fits the Pythagorean Theorem.
So your question is: "Do 2, 6, and 8 form a Pythagorean triple ?", and the answer
is either 'yes' or 'no'.
(2)2 = 4
(6)2 = 36
4 + 36 = 40
(8)2 = 64
40 is not equal to 64.
So the answer is "no".
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No.
To calculate the diagonal, use the Pythagorean Theorem.6^2 + 6^2 = x^236 + 36 = x^272 = x^2sqrt72 = xx = 8.485.....
If the sides of a right angle triangle are 6 feet and 8 feet then by using Pythagoras' theorem the hypotenuse will be 10 feet
The important thing here is that it's a right triangle. Since it is, you can use the Pythagorean theorem. The Pythagorean theorem is as follows... (Length of leg)^2 + (Length of leg)^2 = (Hypotenuse)^2 6^2 + 8^2 = h^2 36 + 64 + h^2 100 = h^2 (Now extract the root from both sides) 10=h
Pythagorean Theorem a^2 + b^2 = c^2 where c is the hypotenuse c =sqrt(6^2 + 8^2) c = sqrt(100) = 10