No, it is not.
2
The fourth root of 16 is 2
2-1/4 = 1/21/4 = 1/fourth root of 2If your range is the real numbers, the fourth root of 2 is ±1.189 so that the answer is ±1/1.189 = ±0.841 approx.However, if your range is the complex field, you will also have the values ±0.841*i where i is the imaginary square root of -1.
Take the square root of the square root of the number (that is the fourth root of the number), for example: √√16 = √(√16) = √4 = 2 24 = 16 ⇒ 2 is the fourth root of 16.
400-256 = b^2 144 = b^2 144^-2 [square root of 144] = b ? = b you can do the rest!
2 and -2.
2i, which isn't real, but only possible answer.
The fourth root of 16 is 2. 2 * 2 = 4, * 2 = 8, * 2 = 16.
2
Well, butter my biscuit, if you take the 8th root of 256, you get 2. So, 2 to the power of 8 equals 256. Math can be a real hoot when you know your roots and powers!
The prime factorization of 256 is 28. The square root is 24 or 16.
The fourth root of 16 is 2
4^4=4*4*4*4 = 256 OR (2^2)^4 = 2^8 = 256
2-1/4 = 1/21/4 = 1/fourth root of 2If your range is the real numbers, the fourth root of 2 is ±1.189 so that the answer is ±1/1.189 = ±0.841 approx.However, if your range is the complex field, you will also have the values ±0.841*i where i is the imaginary square root of -1.
Look for the largest square number in its factors. The square root of 512 is equal to the square root of 2 times the square root of 256. The square root of 256 is 16. The square root of 512 simplifies to 16 times the square root of 2.
2
The 4th root of 16 is 2