2
The fourth root of 16 is 2
2-1/4 = 1/21/4 = 1/fourth root of 2If your range is the real numbers, the fourth root of 2 is ±1.189 so that the answer is ±1/1.189 = ±0.841 approx.However, if your range is the complex field, you will also have the values ±0.841*i where i is the imaginary square root of -1.
Take the square root of the square root of the number (that is the fourth root of the number), for example: √√16 = √(√16) = √4 = 2 24 = 16 ⇒ 2 is the fourth root of 16.
400-256 = b^2 144 = b^2 144^-2 [square root of 144] = b ? = b you can do the rest!
2 and -2.
2i, which isn't real, but only possible answer.
The fourth root of 16 is 2. 2 * 2 = 4, * 2 = 8, * 2 = 16.
2
The prime factorization of 256 is 28. The square root is 24 or 16.
The fourth root of 16 is 2
4^4=4*4*4*4 = 256 OR (2^2)^4 = 2^8 = 256
2-1/4 = 1/21/4 = 1/fourth root of 2If your range is the real numbers, the fourth root of 2 is ±1.189 so that the answer is ±1/1.189 = ±0.841 approx.However, if your range is the complex field, you will also have the values ±0.841*i where i is the imaginary square root of -1.
Look for the largest square number in its factors. The square root of 512 is equal to the square root of 2 times the square root of 256. The square root of 256 is 16. The square root of 512 simplifies to 16 times the square root of 2.
Two to the power 8 (28) is 256 The square root of 256 is 16. When you take the square root of a number raised to a power y, divide that power by 2 (y/2) and that gives the square root. So the square root of 28 = 28/2 = 24 = 16
Well, well, well, someone's got a math problem on their hands! Let me break it down for you - if you take a number, square root it, and then double it, and you end up with 32, that number you started with must be 8. So, there you have it, 8 is the magic number in this little math equation of yours.
The 4th root of 16 is 2