No, it is not.
2
The fourth root of 16 is 2
The fourth root of 16 is found by determining the number that, when raised to the power of 4, equals 16. Since (2^4 = 16), the fourth root of 16 is 2. Thus, the fourth root of 16 is 2.
2-1/4 = 1/21/4 = 1/fourth root of 2If your range is the real numbers, the fourth root of 2 is ±1.189 so that the answer is ±1/1.189 = ±0.841 approx.However, if your range is the complex field, you will also have the values ±0.841*i where i is the imaginary square root of -1.
The square root of 512 is approximately 22.63. In exact terms, it can be expressed as ( 16\sqrt{2} ) since ( 512 = 256 \times 2 ) and ( \sqrt{256} = 16 ).
2 and -2.
2i, which isn't real, but only possible answer.
The fourth root of 16 is 2. 2 * 2 = 4, * 2 = 8, * 2 = 16.
2
Well, butter my biscuit, if you take the 8th root of 256, you get 2. So, 2 to the power of 8 equals 256. Math can be a real hoot when you know your roots and powers!
The prime factorization of 256 is 28. The square root is 24 or 16.
The fourth root of 16 is 2
4^4=4*4*4*4 = 256 OR (2^2)^4 = 2^8 = 256
2-1/4 = 1/21/4 = 1/fourth root of 2If your range is the real numbers, the fourth root of 2 is ±1.189 so that the answer is ±1/1.189 = ±0.841 approx.However, if your range is the complex field, you will also have the values ±0.841*i where i is the imaginary square root of -1.
Look for the largest square number in its factors. The square root of 512 is equal to the square root of 2 times the square root of 256. The square root of 256 is 16. The square root of 512 simplifies to 16 times the square root of 2.
The 4th root of 16 is 2
2