b^(2) = a Then b = +/- sqrt(a)
the square root of B
a = 11 and b = 5.
b = sqrt32 or 4 root 2
b. -4x2+20 = 4x2 = 4-20x2 = -16x = -4Note that -42 = -16 but (-4)2 in brackets = 16
b^(2) = a Then b = +/- sqrt(a)
root 7
the square root of B
a = 11 and b = 5.
The square-root of B2 is +B and also -B .
b is the square root of 5/3
b = sqrt32 or 4 root 2
b. -4x2+20 = 4x2 = 4-20x2 = -16x = -4Note that -42 = -16 but (-4)2 in brackets = 16
Yes, the answer is the square root of 2b.
a=24 b=16 c=18
20
(11, 5)