Yes, It is a solution (a+)
To determine if 2 is a solution to the inequality (x), we need to clarify the specific inequality being referenced. If we're considering a simple inequality such as (x > 1), then 2 is indeed a solution because it satisfies the condition. However, if the inequality is (x < 1), then 2 would not be a solution. Please provide the complete inequality for an accurate assessment.
To solve the inequality ( x^2 < 9 ), we first rewrite it as ( x^2 - 9 < 0 ), which factors to ( (x - 3)(x + 3) < 0 ). The critical points are ( x = -3 ) and ( x = 3 ). Analyzing the intervals, we find that the solution to the inequality is ( -3 < x < 3 ). Therefore, the values of ( x ) that satisfy the inequality are those in the open interval ( (-3, 3) ).
To determine a solution to an inequality, you need to specify the inequality itself. Solutions vary depending on the inequality's form, such as linear (e.g., (x > 3)) or quadratic (e.g., (x^2 < 4)). Once the inequality is provided, you can identify specific numbers that satisfy it. Please provide the inequality for a precise solution.
The inequality ( x^3 < 3 ) can be solved by finding the integer values of ( x ) that satisfy this condition. To do this, we first note that ( x^3 = 3 ) has a real solution at ( x = \sqrt[3]{3} \approx 1.442 ). The integer solutions for the inequality ( x^3 < 3 ) are thus ( x = -2, -1, 0, 1 ). Therefore, the integer solutions are ( x \in {-2, -1, 0, 1} ).
Linear inequalities are equations, but instead of an equal sign, it has either a greater than, greater than or equal to, less than, or a less than or equal to sign. Both can be graphed. Solving linear equations mainly differs from solving linear inequalities in the form of the solution. 1. Linear equation. For each linear equation in x, there is only one value of x (solution) that makes the equation true. The equation: x - 3 = 7 has one solution, that is x = 10. The equation: 3x + 4 = 13 has one solution that is x = 3. 2. Linear inequality. On the contrary, a linear inequality has an infinity of solutions, meaning there is an infinity of value of x that make the inequality true. All these x values constitute the "solution set" of the inequality. The answers of a linear inequality are expressed in the form of intervals. The linear inequality x + 5 < 9 has as solution: x < 4. The solution set of this inequality is the interval (-infinity, 4) The inequality 4x - 3 > 5 has as solution x > 2. The solution set is the interval (2, +infinity). The intervals can be open, closed, and half closed. The open interval (1, 4) ; the 2 endpoints 1 and 4 are not included in the solution set. The closed interval [-2, 5] ; the 2 end points -2 and 5 are included. The half-closed interval [3, +infinity) ; the end point 3 is included.
No, it is not a solution.
To determine if 2 is a solution to the inequality (x), we need to clarify the specific inequality being referenced. If we're considering a simple inequality such as (x > 1), then 2 is indeed a solution because it satisfies the condition. However, if the inequality is (x < 1), then 2 would not be a solution. Please provide the complete inequality for an accurate assessment.
If 7 > 3x - 2 then x < 3.
To solve the inequality ( x^2 < 9 ), we first rewrite it as ( x^2 - 9 < 0 ), which factors to ( (x - 3)(x + 3) < 0 ). The critical points are ( x = -3 ) and ( x = 3 ). Analyzing the intervals, we find that the solution to the inequality is ( -3 < x < 3 ). Therefore, the values of ( x ) that satisfy the inequality are those in the open interval ( (-3, 3) ).
To determine a solution to an inequality, you need to specify the inequality itself. Solutions vary depending on the inequality's form, such as linear (e.g., (x > 3)) or quadratic (e.g., (x^2 < 4)). Once the inequality is provided, you can identify specific numbers that satisfy it. Please provide the inequality for a precise solution.
Solve the inequality and enter your solution as an inequality comparing the variable to the solution. -33+x<-33
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
Yes
The inequality ( x^3 < 3 ) can be solved by finding the integer values of ( x ) that satisfy this condition. To do this, we first note that ( x^3 = 3 ) has a real solution at ( x = \sqrt[3]{3} \approx 1.442 ). The integer solutions for the inequality ( x^3 < 3 ) are thus ( x = -2, -1, 0, 1 ). Therefore, the integer solutions are ( x \in {-2, -1, 0, 1} ).
Linear inequalities are equations, but instead of an equal sign, it has either a greater than, greater than or equal to, less than, or a less than or equal to sign. Both can be graphed. Solving linear equations mainly differs from solving linear inequalities in the form of the solution. 1. Linear equation. For each linear equation in x, there is only one value of x (solution) that makes the equation true. The equation: x - 3 = 7 has one solution, that is x = 10. The equation: 3x + 4 = 13 has one solution that is x = 3. 2. Linear inequality. On the contrary, a linear inequality has an infinity of solutions, meaning there is an infinity of value of x that make the inequality true. All these x values constitute the "solution set" of the inequality. The answers of a linear inequality are expressed in the form of intervals. The linear inequality x + 5 < 9 has as solution: x < 4. The solution set of this inequality is the interval (-infinity, 4) The inequality 4x - 3 > 5 has as solution x > 2. The solution set is the interval (2, +infinity). The intervals can be open, closed, and half closed. The open interval (1, 4) ; the 2 endpoints 1 and 4 are not included in the solution set. The closed interval [-2, 5] ; the 2 end points -2 and 5 are included. The half-closed interval [3, +infinity) ; the end point 3 is included.
y - x - 3 is an expression, not an equation nor an inequality. It cannot, therefore, have a solution.
-2