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x+7 is greater than or equal to 2
One possible inequality that has x = 0.8 as a solution is x ≤ 0.8. This means that any value of x that is less than or equal to 0.8 will satisfy the inequality.
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.
5x-3 < 3x+1 5x-3x < 1+3 2x < 4 Divide both sides of the inequality by 2 to find the value of x: x < 2 So x is an integer whose value is less than 2 such as 1, 0, -1, -2, -3, .........
Call the unknown integer x. Then, from the problem statement, x - 3/x = 26/3, or:x2 - 3 = 26x/3; or x2 - (26/3)x - 3 = 0x = 9