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The inequality ( x^3 < 3 ) can be solved by finding the integer values of ( x ) that satisfy this condition. To do this, we first note that ( x^3 = 3 ) has a real solution at ( x = \sqrt[3]{3} \approx 1.442 ). The integer solutions for the inequality ( x^3 < 3 ) are thus ( x = -2, -1, 0, 1 ). Therefore, the integer solutions are ( x \in {-2, -1, 0, 1} ).
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Which lists all the integer solutions of the inequality x 3?
The inequality ( x < 3 ) includes all integer solutions that are less than 3. Therefore, the integer solutions are ( \ldots, -2, -1, 0, 1, 2 ). In interval notation, this can be expressed as ( (-\infty, 3) ) for the integers.
How do you find the integer solution of the inequality x 2?
To find the integer solutions of the inequality ( x^2 < n ) (where ( n ) is a positive integer), first determine the square root of ( n ). The integer solutions for ( x ) will be all integers satisfying ( -\sqrt{n} < x < \sqrt{n} ). This means you consider all integers from ( -\lfloor \sqrt{n} \rfloor ) to ( \lfloor \sqrt{n} \rfloor ), excluding the endpoints if ( n ) is a perfect square.
What is the least possible integer solution of the inequality 4.103x19.868?
To find the least possible integer solution of the inequality (4.10 < 3x < 19.86), we first solve for (x) by dividing the entire inequality by 3. This gives us (1.3667 < x < 6.62). The least integer greater than (1.3667) is (2). Therefore, the least possible integer solution is (2).
Which values are solutions to the inequality x2 9?
To solve the inequality ( x^2 < 9 ), we first rewrite it as ( x^2 - 9 < 0 ), which factors to ( (x - 3)(x + 3) < 0 ). The critical points are ( x = -3 ) and ( x = 3 ). Analyzing the intervals, we find that the solution to the inequality is ( -3 < x < 3 ). Therefore, the values of ( x ) that satisfy the inequality are those in the open interval ( (-3, 3) ).
Will an equation with an integer coefficient always have an integer solution?
No, an equation with integer coefficients does not always have an integer solution. For example, the equation (x + 1 = 2) has an integer solution, (x = 1), but the equation (2x + 3 = 1) has no integer solution since (x = -1) is not an integer. Solutions depend on the specific equation and its constraints, and rational or real solutions may exist instead.
Which lists all the integer solutions of the inequality x 3?
The inequality ( x < 3 ) includes all integer solutions that are less than 3. Therefore, the integer solutions are ( \ldots, -2, -1, 0, 1, 2 ). In interval notation, this can be expressed as ( (-\infty, 3) ) for the integers.
What are the integer solutions of the inequality x 4?
4 & |-4|
What are at least five inequality solutions to x-3?
x - 3 is not an inequality.
What is Graph all positive integer solutions of the inequality x?
It seems there's a part of your question missing regarding the specific inequality involving ( x ). However, if you're referring to a general inequality like ( x > 0 ), the graph would consist of all points on the number line to the right of the origin (0), representing all positive integer solutions: ( 1, 2, 3, \ldots ). If you provide the specific inequality, I can give a more tailored response!
How do you find the integer solution of the inequality x 2?
To find the integer solutions of the inequality ( x^2 < n ) (where ( n ) is a positive integer), first determine the square root of ( n ). The integer solutions for ( x ) will be all integers satisfying ( -\sqrt{n} < x < \sqrt{n} ). This means you consider all integers from ( -\lfloor \sqrt{n} \rfloor ) to ( \lfloor \sqrt{n} \rfloor ), excluding the endpoints if ( n ) is a perfect square.
What is the least possible integer solution of the inequality 4.103x19.868?
To find the least possible integer solution of the inequality (4.10 < 3x < 19.86), we first solve for (x) by dividing the entire inequality by 3. This gives us (1.3667 < x < 6.62). The least integer greater than (1.3667) is (2). Therefore, the least possible integer solution is (2).
Which values are solutions to the inequality x2 9?
To solve the inequality ( x^2 < 9 ), we first rewrite it as ( x^2 - 9 < 0 ), which factors to ( (x - 3)(x + 3) < 0 ). The critical points are ( x = -3 ) and ( x = 3 ). Analyzing the intervals, we find that the solution to the inequality is ( -3 < x < 3 ). Therefore, the values of ( x ) that satisfy the inequality are those in the open interval ( (-3, 3) ).
Will an equation with an integer coefficient always have an integer solution?
No, an equation with integer coefficients does not always have an integer solution. For example, the equation (x + 1 = 2) has an integer solution, (x = 1), but the equation (2x + 3 = 1) has no integer solution since (x = -1) is not an integer. Solutions depend on the specific equation and its constraints, and rational or real solutions may exist instead.
Find all integer values of x that make the equation or inequality true x2 equals 9?
that would be limited to 3 and -3 for values of x
What are the solutions to the inequality (x-3)(x plus 5)o?
If you mean (x-3)(x+5) = 0 then x = 3 or x = -5
Does an equation with an integer coefficient always have an integer solution?
No, an equation with integer coefficients does not always have an integer solution. For example, the equation (2x + 3 = 5) has the integer solution (x = 1), but the equation (x^2 + 1 = 0) has no real solutions, let alone integer ones. The existence of integer solutions depends on the specific form and constraints of the equation.
What inequality has 3 and negative 5 as two of its solutions?
x+7 is greater than or equal to 2
