x+7 is greater than or equal to 2
One possible inequality that has x = 0.8 as a solution is x ≤ 0.8. This means that any value of x that is less than or equal to 0.8 will satisfy the inequality.
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.
5x-3 < 3x+1 5x-3x < 1+3 2x < 4 Divide both sides of the inequality by 2 to find the value of x: x < 2 So x is an integer whose value is less than 2 such as 1, 0, -1, -2, -3, .........
Call the unknown integer x. Then, from the problem statement, x - 3/x = 26/3, or:x2 - 3 = 26x/3; or x2 - (26/3)x - 3 = 0x = 9
4 & |-4|
x - 3 is not an inequality.
If you mean (x-3)(x+5) = 0 then x = 3 or x = -5
that would be limited to 3 and -3 for values of x
x+7 is greater than or equal to 2
x^2<25
No, it can be an inequality, such as x+5>2. An inequality usually has (infinitely) many solutions.
sec x = 2 cos x = 1/2 x = PI/3 and x=5PI/3 The period of cosine is 2PI The general solutions are: x= PI/3 + 2nPI, where n is any integer x = 5PI/3+2nPI, where n is any integer
If limited to integer solutions, the answers are: 1*117, 3*39 and 9*13
In solving an inequality you generally use the same methods as for solving an equation. The main difference is that when you multiply or divide each side by a negative, you have to switch the direction of the inequality sign. The solution to an equation is often a single value, but the solution to an inequality is usually an infinite set of numbers, such as x>3.
One possible inequality that has x = 0.8 as a solution is x ≤ 0.8. This means that any value of x that is less than or equal to 0.8 will satisfy the inequality.
There is no equation (or inequality) in the question and so there cannot be any solutions.