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The inequality ( x^3 < 3 ) can be solved by finding the integer values of ( x ) that satisfy this condition. To do this, we first note that ( x^3 = 3 ) has a real solution at ( x = \sqrt[3]{3} \approx 1.442 ). The integer solutions for the inequality ( x^3 < 3 ) are thus ( x = -2, -1, 0, 1 ). Therefore, the integer solutions are ( x \in {-2, -1, 0, 1} ).

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Which lists all the integer solutions of the inequality x 3?

The inequality ( x &lt; 3 ) includes all integer solutions that are less than 3. Therefore, the integer solutions are ( \ldots, -2, -1, 0, 1, 2 ). In interval notation, this can be expressed as ( (-\infty, 3) ) for the integers.


How do you find the integer solution of the inequality x 2?

To find the integer solutions of the inequality ( x^2 &lt; n ) (where ( n ) is a positive integer), first determine the square root of ( n ). The integer solutions for ( x ) will be all integers satisfying ( -\sqrt{n} &lt; x &lt; \sqrt{n} ). This means you consider all integers from ( -\lfloor \sqrt{n} \rfloor ) to ( \lfloor \sqrt{n} \rfloor ), excluding the endpoints if ( n ) is a perfect square.


What is the least possible integer solution of the inequality 4.103x19.868?

To find the least possible integer solution of the inequality (4.10 &lt; 3x &lt; 19.86), we first solve for (x) by dividing the entire inequality by 3. This gives us (1.3667 &lt; x &lt; 6.62). The least integer greater than (1.3667) is (2). Therefore, the least possible integer solution is (2).


Which values are solutions to the inequality x2 9?

To solve the inequality ( x^2 &lt; 9 ), we first rewrite it as ( x^2 - 9 &lt; 0 ), which factors to ( (x - 3)(x + 3) &lt; 0 ). The critical points are ( x = -3 ) and ( x = 3 ). Analyzing the intervals, we find that the solution to the inequality is ( -3 &lt; x &lt; 3 ). Therefore, the values of ( x ) that satisfy the inequality are those in the open interval ( (-3, 3) ).


Will an equation with an integer coefficient always have an integer solution?

No, an equation with integer coefficients does not always have an integer solution. For example, the equation (x + 1 = 2) has an integer solution, (x = 1), but the equation (2x + 3 = 1) has no integer solution since (x = -1) is not an integer. Solutions depend on the specific equation and its constraints, and rational or real solutions may exist instead.

Related Questions

What are the integer solutions of the inequality x 4?

4 &amp; |-4|


What are at least five inequality solutions to x-3?

x - 3 is not an inequality.


How do you find the integer solution of the inequality x 2?

To find the integer solutions of the inequality ( x^2 &lt; n ) (where ( n ) is a positive integer), first determine the square root of ( n ). The integer solutions for ( x ) will be all integers satisfying ( -\sqrt{n} &lt; x &lt; \sqrt{n} ). This means you consider all integers from ( -\lfloor \sqrt{n} \rfloor ) to ( \lfloor \sqrt{n} \rfloor ), excluding the endpoints if ( n ) is a perfect square.


What is the least possible integer solution of the inequality 4.103x19.868?

To find the least possible integer solution of the inequality (4.10 &lt; 3x &lt; 19.86), we first solve for (x) by dividing the entire inequality by 3. This gives us (1.3667 &lt; x &lt; 6.62). The least integer greater than (1.3667) is (2). Therefore, the least possible integer solution is (2).


Which values are solutions to the inequality x2 9?

To solve the inequality ( x^2 &lt; 9 ), we first rewrite it as ( x^2 - 9 &lt; 0 ), which factors to ( (x - 3)(x + 3) &lt; 0 ). The critical points are ( x = -3 ) and ( x = 3 ). Analyzing the intervals, we find that the solution to the inequality is ( -3 &lt; x &lt; 3 ). Therefore, the values of ( x ) that satisfy the inequality are those in the open interval ( (-3, 3) ).


Will an equation with an integer coefficient always have an integer solution?

No, an equation with integer coefficients does not always have an integer solution. For example, the equation (x + 1 = 2) has an integer solution, (x = 1), but the equation (2x + 3 = 1) has no integer solution since (x = -1) is not an integer. Solutions depend on the specific equation and its constraints, and rational or real solutions may exist instead.


Find all integer values of x that make the equation or inequality true x2 equals 9?

that would be limited to 3 and -3 for values of x


What are the solutions to the inequality (x-3)(x plus 5)o?

If you mean (x-3)(x+5) = 0 then x = 3 or x = -5


Does an equation with an integer coefficient always have an integer solution?

No, an equation with integer coefficients does not always have an integer solution. For example, the equation (2x + 3 = 5) has the integer solution (x = 1), but the equation (x^2 + 1 = 0) has no real solutions, let alone integer ones. The existence of integer solutions depends on the specific form and constraints of the equation.


What inequality has 3 and negative 5 as two of its solutions?

x+7 is greater than or equal to 2


What are Solution of an inequality?

The solution of an inequality is a set of values that satisfy the inequality condition. For example, in the inequality ( x &gt; 3 ), the solution includes all numbers greater than 3, such as 4, 5, or any number approaching infinity. Solutions can be expressed as intervals, such as ( (3, \infty) ), or as a number line representation. These solutions help identify the range of values that make the inequality true.


Which is true of the infinite solutions of the inequality X0?

The statement &quot;X0&quot; is unclear, but if you are referring to an inequality such as x &gt; 0 or x ≤ 0, it indicates that there are infinite solutions within the specified range. For instance, if the inequality is x &gt; 0, the solutions include all positive real numbers. These solutions can be represented on a number line or in interval notation, such as (0, ∞) for x &gt; 0.