To solve the inequality ( x^2 < 9 ), we first rewrite it as ( x^2 - 9 < 0 ), which factors to ( (x - 3)(x + 3) < 0 ). The critical points are ( x = -3 ) and ( x = 3 ). Analyzing the intervals, we find that the solution to the inequality is ( -3 < x < 3 ). Therefore, the values of ( x ) that satisfy the inequality are those in the open interval ( (-3, 3) ).
If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9
Three solutions for inequality in Year 9 math include: Graphing: Plotting the inequality on a graph helps visualize the solution set, showing all the points that satisfy the inequality. Substitution: Testing specific values in the inequality can help determine if they satisfy the condition, providing a practical way to find solutions. Algebraic Manipulation: Rearranging the inequality by isolating the variable can simplify the problem and lead directly to the solution set.
x2 + 6x = 7 ⇒ x2 + 6x + 9 = 7 + 9 ⇒ (x + 3)2 = 16 ⇒ x + 3 = ±4 ⇒ x = -7 or 1
x2+4x-9 = 5x+3 x2+4x-5x-9-3 = 0 x2-x-12 = 0 (x+3)(x-4) = 0 x = -3 or x = 4
Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
that would be limited to 3 and -3 for values of x
If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9
Three solutions for inequality in Year 9 math include: Graphing: Plotting the inequality on a graph helps visualize the solution set, showing all the points that satisfy the inequality. Substitution: Testing specific values in the inequality can help determine if they satisfy the condition, providing a practical way to find solutions. Algebraic Manipulation: Rearranging the inequality by isolating the variable can simplify the problem and lead directly to the solution set.
x2 = 81 Square root both sides:- x = +/- 9
Therefore x2=9+y2. And x is the square-root of that (with two values plus and minus). Choose a value of y, and work out x2 and therefore the values of x. Plot the two (+ and -) on a graph and continue for more values of y.
x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)
To determine if ( x^2 - 9 ) is a solution or no solution, we need more context, such as an equation or inequality to solve. If you are asking if ( x^2 - 9 = 0 ) has solutions, then yes, it does, as it can be factored to ( (x - 3)(x + 3) = 0 ), giving solutions ( x = 3 ) and ( x = -3 ). If you're referring to something else, please provide additional details.
x2 + 6x = 7 ⇒ x2 + 6x + 9 = 7 + 9 ⇒ (x + 3)2 = 16 ⇒ x + 3 = ±4 ⇒ x = -7 or 1
x2+4x-9 = 5x+3 x2+4x-5x-9-3 = 0 x2-x-12 = 0 (x+3)(x-4) = 0 x = -3 or x = 4
Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
The answer is -16.
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.