Yes, 321 is divisible by 3 because the sum of its digits (3 + 2 + 1) equals 6, which is a multiple of 3.
321 is divisible by these four numbers: 1, 3, 107, 321.
No - 321/2 = 160.5.
No.
If a number is divisible by 2 and 3, it is divisible by 6.
Yes, 321 is divisible by 3 because the sum of its digits (3 + 2 + 1) equals 6, which is a multiple of 3.
321 is divisible by these four numbers: 1, 3, 107, 321.
No - 321/2 = 160.5.
By any of its factors which are: 1, 3, 107 and 321
No.
No.
Out of that list, only 3.
Both are divisible by 3.
1, 2, 3, 6, 107, 214, 321, 642
Yes, and the answer to 9/12321 is 0.00073046018.
53.5
642 is composite. It is divisible by 2, 3, 107, 214, and 321.