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How many numbers between 201 and 301 are divisible by both 3 and 4?
To be divisible by 3 and 4 the number must be divisible by 12. 201/12 = 16.75 so the smallest number in the range, divisible by 12, is 17*12 = 204 301/12 = 25.08 so the largest number in the range, divisible by 12, is 25*12 = 300 The number of multiples of 12 is 25 - 16 = 9
How do you find the divisibility rule for nine?
If a numbers digits add up to a number that is divisible by nine, the number is divisible by nine. Example~ 486 4+8+6=18 Since 18 is divisible by 9, 486 is divisible by 9. 561 5+6+1=12. 561 isn't divisible by 9.
What numbers is not divisible by 9 81 162 199 1125?
81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9. So 199 is the only one not divisible by 9.
Is 741 divisible by 3 4 5 6 9 10?
7 + 4 + 1 = 12 which is divisible by 3, so 741 is divisible by 3 741 is odd, all multiples of 4 are even, 741 is not divisible by 4 (Alternatively 4 x 2 + 1 x 1 = 9 which is not divisible by 4, so 741 not divisible by 4) All multiples of 5 end with 5 or 0, 741 ends with 1, so 741 not divisible by 5 To be divisible by 6, the number must be divisible by 2 (even) and divisible by 3.741 is odd, so not divisible by 2, so 741 is not divisible by 6 7 + 4 + 1 = 12 which is not divisible by 9, so 741 is not divisible by 9 All multiples of 10 end with 0, 741 ends with 1 so 741 is not divisible by 10 Summary: 741 is divisible by 3, but not by 4, 5, 6, 9 nor 10.
Is 441 divisible by 9?
Yes, 441 is divisible by 9. To determine if a number is divisible by 9, you can add up its digits. In this case, 4 + 4 + 1 = 9, which is divisible by 9. Therefore, 441 is divisible by 9.
