If a number is divisible by both three and four, it's divisible by twelve.
The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48 The factors of 321 are: 1, 3, 107, 321
All multiples of 12, which is an infinite number.
Both are divisible by 3 and 5 12/3 = 4 12/5 = 2.4 601848/3 = 200616 601848/5 = 40123.2 However both are only divisible by 3 with no remainder.
Any multiple of 96.
321 is divisible by these four numbers: 1, 3, 107, 321.
Yes, and the answer to 9/12321 is 0.00073046018.
321 / 6 = 53.5
No - 321/2 = 160.5.
By any of its factors which are: 1, 3, 107 and 321
No.
No.
Yes, 321 is divisible by 3 because the sum of its digits (3 + 2 + 1) equals 6, which is a multiple of 3.
Both are divisible by 3.
The GCF for 12 and 321 is 3.
642 is composite. It is divisible by 2, 3, 107, 214, and 321.
145 is not divisible by 12.