Oh, dude, let me break it down for you. So, 34515 is definitely divisible by 3 because if you add up all the digits (3 + 4 + 5 + 1 + 5), you get 18, which is divisible by 3. As for 9, well, since 3 divides into it, 9 will too because 9 is just 3 times 3. And 5? Well, it doesn't end in 0 or 5, so it's not divisible by 5. So, yeah, 34515 is divisible by 3 and 9, but not 5.
To determine if 34515 is divisible by 3, we can add the digits together: 3+4+5+1+5 = 18, which is divisible by 3. Therefore, 34515 is divisible by 3. To check if it is divisible by 9, we would need to further reduce the sum of the digits to see if it is a multiple of 9. In this case, 1+8 = 9, which is a multiple of 9, so 34515 is divisible by 9. To check for divisibility by 5, we simply need to look at the last digit, which is 5 in this case. Since 5 is a factor of 34515, it is divisible by 5.
Three is a factor of nine.
2 and 3Today, people don't explain why a number has to be divisible by 2 and 3 to be divisible by 6 or how it works.
At least one of the four will be divisible by 4. One other will be divisible by 2 (but not by 4) One other will be divisible by 3. Hence the product will be divisible by 4 x 2 x 3 = 24.
Yes, it is. The digital root of 1430061, that is, the sum of all its digits is 1+4+3+0+0+6+1 = 15 The digital root of 15 is 1+5 = 6 which is divisible by 3. So 1430061 is divisible by 3.
21 has factors other than 1 and itself, so it is not a prime number. For example, it is divisible by 3. (You can check this by adding the digits of the number: 2 + 1 = 3. If the sum of the digits is divisible by 3, the number is also divisible by 3.) Therefore, 21 is a composite number.
Yes look at the last numbers and the answer is 11505 and I did that simply in my head
Because 9 is a multiple of 3.
793 is not divisible by 3. I'm not sure how much explanation that requires.
Three is a factor of nine.
2 and 3Today, people don't explain why a number has to be divisible by 2 and 3 to be divisible by 6 or how it works.
No. To find whether the number is divisible by 3, you add each digits and if it's equal to 9 then it's divisible by 3 because 9 is divisible by 3. 9 + 8 + 2 = 19, 1 + 9 = 10... so it's not divisible by 3.
In mathematics, deductive reasoning is used in proofs of geometric theorems. Inductive reasoning is used to simplify expressions and solve equations.
At least one of the four will be divisible by 4. One other will be divisible by 2 (but not by 4) One other will be divisible by 3. Hence the product will be divisible by 4 x 2 x 3 = 24.
Explain why you are pasting your homework questions straight into WikiAnswers.
Yes, it is. The digital root of 1430061, that is, the sum of all its digits is 1+4+3+0+0+6+1 = 15 The digital root of 15 is 1+5 = 6 which is divisible by 3. So 1430061 is divisible by 3.
No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.
492 is an even number so it must be divisible by 2. Its digits total a multiple of 3 so it must be divisible by 3. Any even number that is divisible by 3 is divisible by 6. Of course, you can always divide 492 by 6. If it comes out even, it's a factor. (It does.)