No they are not.Two numbers are relatively prime if their greatest common factor is 1.For example, 8 and 15 are relatively prime.
No. 5 is a multiple of it.
The four prime numbers that multiply together to make 945 are 3, 3, 5, and 7. Specifically, the prime factorization of 945 is (3^2 \times 5 \times 7). Thus, the unique prime factors involved are 3, 5, and 7.
3 x 3 x 3 x 5 x 7 = 945
No, they are not relatively prime.
2 and 3
Both are composite as 384 = 27 x 3, 945 = 33 x 5 x 7, and they are relatively prime.
As a product of its prime factors: 3*3*3*5*7 = 945
907 + 31 + 5 + 2 = 945
945 = 33 x 5 x 7
3 x 3 x 3 x 5 x 7 = 945
The factors of 945 are 1 3 5 7 9 15 21 27 35 45 63 105 135 189 315 945. The prime factors of 945 are 3, 5, and 7.
No. 5 is a multiple of it.
As a product of its prime factors: 3*3*3*5*7 = 945
3 x 3 x 3 x 5 x 7 = 945
945 315,3 105,3,3 35,3,3,3 7,5,3,3,3 3 x 3 x 3 x 5 x 7 = 945
3 x 3 x 3 x 5 x 7 = 945
3 x 3 x 3 x 5 x 7 = 945 33 x 5 x 7 = 945