x = 3, y = 9 is one solution from infinite number of solutions.
to find another solution just choose any number for x, substitue it in the equation, for example if x = 1, y= 4 * 1 - 3 = 1, so 1 and 1 is another solution for y = 4 x - 3
In this question there is only one equation which contains two variables, so there is no unique solution.
we need other independent equation contains the variables x and y then we can solve these equations simultaneously, i.e. we can find finite number of solution (its one solution in linear equations)
-3x = 9x = 9/(-3)x = -3
That's an invalid equation.
The solution is all points on the line y = x + 3, for example (0, 3) (1, 4), (2.567, 5.567).
y= -9
4x + 2y = 12 3x - 2y = 9 Have to use simultaneous equations, so add together to get : 7x = 21 so x = 3 Put it into any part of the equation 4x3 + 2y = 12 12 + 2y = 12 2y = 0 y = 0, x = 3
1
The solution is k = 9.
-3x = 9x = 9/(-3)x = -3
That's an invalid equation.
(x, y) = (3, 7) is a solution.
21-4x3 is equal to 9.
4 * 3=12 * 2-X-3 12=24-(X+3) 0=12-(X+3) 0=X-9 X=-9
4x3+12x2+3x+9
x=9 is as simple as it gets. The question is the solution.
3X = 9 divide both sides integers by 3 (3/3)X = 9/3 X = 3 -------------check in original equation, put 3 in for X 3(3) = 9 9 = 9 ----------checks
it could be anything. What is a? if it is 3 then you do 4x3=12+3x3=9+3=24 * * * * * It is 8a.
The solution is all points on the line y = x + 3, for example (0, 3) (1, 4), (2.567, 5.567).