0
4 * 3=12 * 2-X-3
12=24-(X+3)
0=12-(X+3)
0=X-9
X=-9
What else can I help you with?
What degree polynomial equation is 4x3 plus 7x2 - 4x equals 0?
The "degree" is the highest power - in this case, the 3 in 4x3 (4 times to the third power).
How do you solve x2 81 equals 0?
x: x2 - 81 = 0
Solve the quadratic equation y2-15 equals 0?
y=±√15
Solve the system of equations Enter your answer as an ordered pair 4x plus 8y equals 16 4x minus 8y equals 0?
16
4 x 3 x x 2 0?
4x3=12x20=240the answer to 4x3xx20 is 240
What degree polynomial equation is 4x3 plus 7x2 - 4x equals 0?
The "degree" is the highest power - in this case, the 3 in 4x3 (4 times to the third power).
How do you solve 2Sinx 1 equals 0?
2sinx+1 equals 0
How do you solve y-2y'-3y equals 0?
For y - 2y - 3y equals 0, y equals 0.
How do you solve 2x plus y equals 0 and 4x plus 2y equals 0?
many solutions
How do you solve x equals 0 inequality?
"x equals 0" is an equality, not an inequality. The question is, therefore, not consistent.
How do you solve x³-4x equals 0 algebraically?
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.
How do you solve x2 81 equals 0?
x: x2 - 81 = 0
How do you solve 16t squared minus 9 equals 0?
Solve this problem -x squared -40x- 80 =0
How do you solve 3xx-6 equals 0?
x=2
How do you solve 10x equals x?
10x=x 9x=0 x=0
How do you solve 8m equals 0?
Divide both sides by 8: m = 0
How to solve 4x3 plus 0.4x2 plus 0.01x-2.4x10-18 equals 0?
There are a number of ways. One possibility is the iterative method. Rewrite the equation so as to make x the subject: 4x3 + 0.4x2 + 0.01x - 2.4*10-18 = 0 4x3 = 2.4*10-18 - 0.4x2 - 0.01x x3 = (2.4*10-18 - 0.4x2 - 0.01x)/4 x = cuberoot[(2.4*10-18 - 0.4x2 - 0.01x)/4] The original equation is approximately equal to 4x3 + 0.4x2 + 0.01x = 0 or x*(20x - 1)2 = 0 which has roots at x = 0 and x = -0.05 Start with a value, x1 near one of these roots and use the iteration: xn+1 = cuberoot[(2.4*10-18 - 0.4xn2 - 0.01xn)/4] where n = 1, 2, 3, etc to improve your estimates. The resulting roots are, not surprisingly, 0 and -0.05 to 10 decimal places.
