Rearrange the equations to show 6y = 3x + 14 and 9y = -18x - 14.
This gives you the gradients of the two straight lines.
y = 3/6 x + 14/6 and y = -18/ 9 x - 14/9.
The first shows a gradient of 3/6 and the second is -18/9. These are called the co-efficients of x in each equation.
The two gradients cancel down to 1/2 and -2.
One is the negative reciprocal of the other, so the two lines are not parrallel. They a perpendicular to each other.
The discriminant is 0.
(2x4) + (8x3) + 18x 8 + 24 + 18x 32 + 18x
11x = 20x +1811x-20x=18x(11-20)=18-9x=18x=-2
2x2+18x = 20 2x2+18x-20 = 0 x2+9x-10 = 0 (x+10)(x-1) = 0 x = -10 or x = 1
It has one double solution.
The discriminant is 0.
(2x4) + (8x3) + 18x 8 + 24 + 18x 32 + 18x
11x = 20x +1811x-20x=18x(11-20)=18-9x=18x=-2
2x2+18x = 20 2x2+18x-20 = 0 x2+9x-10 = 0 (x+10)(x-1) = 0 x = -10 or x = 1
It has one double solution.
10x + 17 = 4x - 16x = -18x = -3
18x + 12y = 72 to get x-int. put y=0 18x + (12)(0) = 72 18x = 72 x = 4 your x-intercept is 4. this is the place where the line goes through the x-axis.
18x= 19818x/18 = 198/18x = 11
-5 + 12x = 18x + 7Subtract 7 from each side:-12 + 12x = 18xSubtract 12x from each side:-12 = 6xDivide each side by 6:-2 = x
y=-18x+17. Since this is already in Slope-Intercept form, we can determine that the slope is negative 18.
-122 +18x cant be simplified
18x + 45 or 9(2x + 5) how is this answer figured?