4000 lbs.
To solve the inequality 2t + 1 > 7, we need to isolate the variable t. First, subtract 1 from both sides which gives 2t > 6. Then, divide both sides by 2 to get t > 3. Therefore, t must be greater than 3 for the inequality to hold true.
3r + 3r + 2t = 6r + 2t
19-2t = 7 -2t = 7-19 -2t = -12 t = 6
12(t+6)+8=4(2t-1)+2t 12t+72+8=8t-4+2t 12t-2t-8t=-72-8-4 2t=-84 2t/2=84/2 t=42
4000 lbs.
To solve the inequality 2t + 1 > 7, we need to isolate the variable t. First, subtract 1 from both sides which gives 2t > 6. Then, divide both sides by 2 to get t > 3. Therefore, t must be greater than 3 for the inequality to hold true.
R = s + 2t; s = 3tR = 3t + 2tR = 5t
No, 1 ton equals 2000 pounds. So 4 tons weigh 8000 lbs making it heavier than 7500 lbs.
3r + 3r + 2t = 6r + 2t
You can rewrite the formula as R = 3t^2. Since s is three times greater than t, you can substitute 3t for s in the formula.
2t-3-3 = 7 2t = 7+6 2t = 13 t = 6.5
19-2t = 7 -2t = 7-19 -2t = -12 t = 6
Im not 100% sure but its a call, Yes 2t oil is SAE 30 since its thicker than ATF(SAE 20).
12(t+6)+8=4(2t-1)+2t 12t+72+8=8t-4+2t 12t-2t-8t=-72-8-4 2t=-84 2t/2=84/2 t=42
2t-5t=-3t
2t + 5