No. 135 is divisible by: 1, 3, 5, 9, 15, 27, 45, 135.
No. As 9 is smaller than 45 it cannot be divisible by 45. However, 9 is a FACTOR of 45; and 45 is divisible by 9.
How about 5 x 9 x enough multiples of 10 to give you 5 digits? 5 x 9 = 45 5 x 9 x 10 = 450 5 x 9 x 10 x 10 = 4500 5 x 9 x 10 x 10 x 10 = 45000 18225
90 is divisible by: 1 2 3 5 6 9 10 15 18 30 45 90.
No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.
45 is divisible by 5 and 9 (not 10) because 45 is a multiple of 5 and 9 (not 10).
Yes - as 450 ends in a zero, it is divisible by 10. 450 / 10 = 45.
Nope - it's only divisible by 9 !
No. 135 is divisible by: 1, 3, 5, 9, 15, 27, 45, 135.
No. As 9 is smaller than 45 it cannot be divisible by 45. However, 9 is a FACTOR of 45; and 45 is divisible by 9.
How about 5 x 9 x enough multiples of 10 to give you 5 digits? 5 x 9 = 45 5 x 9 x 10 = 450 5 x 9 x 10 x 10 = 4500 5 x 9 x 10 x 10 x 10 = 45000 18225
45 is divisible by 2 3 4 5 6 7 8 9 10 and 57 and 74 345646 5465 45 346 67542 34743
268 is not divisible by 45 without remainder.
90 is divisible by: 1 2 3 5 6 9 10 15 18 30 45 90.
no, its divisible by... 1,3,5,9,15,45
No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.
yes