As 235 is ending by a 5 then it is divisible by 5 As 235 is not even it is not divisible by 2 As 2+3+5 is not divisible by 3, 235 is not divisible by 3 235/5 = 47 47 is prime so 235 = 5 * 47 and there's no other way to factorize it
47 is a prime number and is divisible by 1 and 47 only. 51 is divisible by 1, 3, 17, 51.
282 is divisible by: 1, 2, 3, 6, 47, 94, 141 and 282.
No. it is not
No.
141 can be divisible by 3. As you can see 141/3 = 47.
As 235 is ending by a 5 then it is divisible by 5 As 235 is not even it is not divisible by 2 As 2+3+5 is not divisible by 3, 235 is not divisible by 3 235/5 = 47 47 is prime so 235 = 5 * 47 and there's no other way to factorize it
142 is not divisible by 3. 142 divided by 3 = 47 and 1/3
47 is a prime number and is divisible by 1 and 47 only. 51 is divisible by 1, 3, 17, 51.
No, 3 is not a factor of 47. A quick way to know that is to add the digits in the number. If they add up to a number that is divisible by 3, the number itself is divisible by 3. If they don't, the number is not divisible by 3.
47 is a prime number 21 & 87 divisible by 3, and 4 is divisible by 2
It is divisible by 3. I'm not sure of anymore.
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282 is divisible by: 1, 2, 3, 6, 47, 94, 141 and 282.
No. 47 is a prime number and is only divisible by 1 and itself.
No. If the sum of the digits of a number is divisible by 3 then the number will be also. In this case, 9+9+8+8+7+6=47 which is not divisible by 3.
3, 7 and 47 are prime numbers. 30 is not a prime since it is divisible by 2, 3, 5, 6, 10 and 15.