As 235 is ending by a 5 then it is divisible by 5
As 235 is not even it is not divisible by 2
As 2+3+5 is not divisible by 3, 235 is not divisible by 3
235/5 = 47
47 is prime so 235 = 5 * 47 and there's no other way to factorize it
If you mean: 2, 3 and 5 then they are 71, 73, 77 and 79
235 is a composite number because it has more than two divisors - contrary to a prime which has exactly two divisors: 1 and the prime itself. 235 has 4 divisors: 1, 5, 47 and 235. A quick way to determine this is done by looking at the last digit. If it is either 0 or 5 the number is divisible by 5, thus it is not a prime.
The number is bigger than 5 but ends in 5 so it is divisible by 5. Therefore it cannot be a prime.
Any number greater than 5 which ends in "5" MUST be divisible by 5, so yes, it's composite.
235 is itself a real number.
It is divisible by 10, but not by 235.
Yes.
235 and its multiples.
235 and its multiples.
No.
No.
No.
No. Nor is it divisible.
One: 235.
2 yes, the rest no.
Yes, the result is 235.
Yes! and the quotient is 47