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Is 20 divisible by 4?
Yes 4 goes into 20 5 times
Is 1124 divisible by 4?
Yes 1124 is divisible by 4. Since 24 is divisible by 4 1124 is divisible by 4. If the last two numbers of a number are divisible by 4, the number is divisible by 4. 24 divided by 4 is 6.
Is 390 divisible by 2 3 4 5 6 9 or 10?
Yes, it is divisible by 2, for a start.
Is 1856 divisible by 4?
yes it is divisible by 4
Is 1255 divisible by 5?
Yes, 1255 is divisible by 5, and any number that ends in 5 is divisible by 5.
Is 384 divisible by 4 and 5?
4, yes.5, no.
Was 1912 a leap year?
Yes - 1912 is divisible by 4.Yes - 1912 is divisible by 4.Yes - 1912 is divisible by 4.Yes - 1912 is divisible by 4.
Is 20 divisible by 4?
Yes 4 goes into 20 5 times
Why are 20 and 25 divisible by 5?
Yes. 20/5 = 4 and 25/5 = 5
Is 148 divisible by 4 or 5?
148 is divisible by 4, not by 5
Is 40 divisible by 2345689 or 10?
Out of that list, 2, 4, 5 and 10.
Is 1124 divisible by 4?
Yes 1124 is divisible by 4. Since 24 is divisible by 4 1124 is divisible by 4. If the last two numbers of a number are divisible by 4, the number is divisible by 4. 24 divided by 4 is 6.
Is 189 divisible by 2 3 4 5 6 9 and 10?
No. 189 is only evenly divisible by 3 and 9 (from the set provided). Using the following rules of divisibility on the number 189: Divisible by 2? No - the number is not even Divisible by 3? Yes - the sum of the digits (1 + 8 + 9 = 18) is divisible by 3 Divisible by 4? No - the last two digits are not evenly divisible by 4 Divisible by 5? No - the last digit is not a 0 or a 5 Divisible by 6? No - the number is not even Divisible by 9? Yes - the sum of the digits is divisible by 9 Divisible by 10? No - the number is not divisible by 2 or 5
Is 62784 divisible by 4?
Yes.
Is 390 divisible by 2 3 4 5 6 9 or 10?
Yes, it is divisible by 2, for a start.
Is 124 divisible by 1 2 3 4 5 6 or 10?
No, it is not divisible by 123456 nor by 10.
Is 5260 divisible by 234569 or 10?
Any element of the set of numbers of the form *k, where k is an integer, is evenly divisible. However, 308 is not evenly divisible by either.
