Oh, dude, let me break it down for you. So, 124 isn't divisible by 3 because if you add up the digits (1 + 2 + 4 = 7), that sum isn't divisible by 3. And 124 isn't divisible by 6 either because it's not an even number. As for 9, nope, it doesn't work because the sum of the digits (1 + 2 + 4 = 7) isn't divisible by 9. So, in conclusion, 124 is just being a rebel and not playing nice with these numbers.
250 is divisible by 1, 2, 5, 10, 25, 50, and 250.
no, it is divisible by 1, 2, 5, 7, 10, 14, 35, 70
650 is divisible by: 650 and 1 65 and 10 130 and 5 325 and 2
124/3 = 41 quotient, remainder 1 Increase quotient 42*3 = 126. difference of 126 and 124 is 2 . So 2 is to be added it is least.
124 is divisible by 4
1, 2, 4, 31, 62, 124
10 is divisible by 1, 2, 5 & 10
It is a statement which is true for some sums.
The rule of thumb is that if the sum of the digits of the number equals a number that is divisible by 3, then the number is divisible by 3.For example,372: 3+7+2 = 12, which is a multiple of 3 (3x4=12)So, 3 is a factor of 372(which is true, as 3 x 124 = 372).124: 1+2+4 = 7, which is not a multiple of 3So, 3 is not a factor of 124(which is true, as 124 is not evenly divisible by 3, 124/3 = 41.33333)
yes because its a even number
1,240 divides evenly by: 1, 2, 4, 5, 8, 10, 20, 31, 40, 62, 124, 155, 248, 310, 620, 1240.
250 is divisible by 1, 2, 5, 10, 25, 50, and 250.
No. 302 is divisible by 1, 2, 151, 302.
No. It is only divisible by 1, 2, 751, 1502.
No one-digit numbers are divisible by 10. 10 is divisible by 1, 2 and 5.
It is divisible only by 3; It is not divisible by 2, 4, 5, 6, 9, 10. 17211 is odd, so not divisible by 2, 4, 6 nor 10. 1 + 7 + 2 + 1 + 1 = 12 which is divisible by 3, so 17211 is divisible by 3, but 12 is not divisible by 9, so 17211 is not divisible by 9. 17211 does not end in 5 or 0 so not divisible by 5