No, (5h + 2h^2) is not equivalent to (7h). The expression (5h + 2h^2) contains a term (2h^2), which is a quadratic term, while (7h) is a linear term. Therefore, they represent different mathematical expressions.
It is: 11h
To simplify the expression (3h - 5h^2 + 3h^3 + 3h - 6h^2 + 7 - 5h + 2h^3), first combine like terms. Grouping them gives: ( (3h + 3h - 5h) + (3h^3 + 2h^3) + (-5h^2 - 6h^2) + 7). This simplifies to (-5h^2 + 5h + 5h^3 + 7). The final expression is (5h^3 - 5h^2 + 5h + 7).
53 x h3
It is the same as 5h+20 = 5(h+4)
No, (5h + 2h^2) is not equivalent to (7h). The expression (5h + 2h^2) contains a term (2h^2), which is a quadratic term, while (7h) is a linear term. Therefore, they represent different mathematical expressions.
h = 0.538462 14 + 5h + 2h = 5h + 28h 14 + 7h = 33h 14 + 7h - 7h = 33h - 7h 14 = 26h 14/26 = 26/26h 0..538462 = h
It is: 11h
Yes 5*7h is the same as 35h
equivalent
Yes, ( 5 \times 7h ) and ( 35h ) are equivalent. When you multiply ( 5 ) by ( 7h ), you get ( 35h ), which means both expressions represent the same value for any value of ( h ). Therefore, they are equivalent expressions.
Assuming that the s refers to seconds, the answer is 5h.
To simplify the expression (3h - 5h^2 + 3h^3 + 3h - 6h^2 + 7 - 5h + 2h^3), first combine like terms. Grouping them gives: ( (3h + 3h - 5h) + (3h^3 + 2h^3) + (-5h^2 - 6h^2) + 7). This simplifies to (-5h^2 + 5h + 5h^3 + 7). The final expression is (5h^3 - 5h^2 + 5h + 7).
53 x h3
It is the same as 5h+20 = 5(h+4)
8w x 5h = 40wh
It is: 12h+5h = 17h