r2 + r - 20 = 0(r + 5)(r - 4) = 0r + 5 = 0 or r - 4 = 0r = -5 or r = 4
6
4 -5 on the r ax = -1
r of planets in the known universe
Since r varies directly with s, we have r = ks (replace k with 5 and s with 7) r = (5)(7) r = 35
In series combination, Current(I) remains same among all the resistors, but voltage(V) changes. So: V(Equivalent) = I(Equivalent) * R(Equivalent) R(Equivalent) = V(Equivalent)/ I(Equivalent) R(Equivalent) = IR1+ IR2+...+IRn / I R(Equivalent) = I(R1+R2+...+Rn)/ I R(Equivalent) = R1+R2+...+Rn
1/R = 1/60 + 1/60+ 1/60+ 1/60 + 1/60 1/R = 5 / 60 R = 60/5 R = 12 ohms.
5(r+5) is.
I?=I source(R equivalent / R?)
13
r2 + r - 20 = 0(r + 5)(r - 4) = 0r + 5 = 0 or r - 4 = 0r = -5 or r = 4
6
Moment of inertia of hollowsphere = 2/5 M(R^5-r^5)/(R^3-r^3)
1 to 6 = 2 to 12
No, they are not.
if: r = 5z 15z = 3y then: z = y/5 r = 5(y/5) r = y
factor out the common monomial, 5. 5(r^3-1) Factor as a difference of cubes. 5(r-1)(r^2+r+1)