No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.
no :)
The number 90 is divisible by both 2 and 3.
Both.
Something divisible by 6 has to be divisible by both 2 and 3. and that just answers that anything disible by 6 is divisible by 2
Yes it is.... 186/2=93 & 186/3=62
No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.
Any number that is divisible by both 2 and 3 is divisible by 6.
2 yes, 3 no.
no :)
2 or 62 no because 5 is not divisible in 2 or 62.
432 is divisible evenly by both 2 and 3
The number 90 is divisible by both 2 and 3.
Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.
Both.
376/6 = 188/3 = 62 and 2/3 or 62.666 (recurring)
To determine if a number is divisible by 6, it must be divisible by both 2 and 3. To determine if a number is divisible by 2, it should be even - in other words, it should end with 0, 2, 4, 6, or 8. To determine if a number is divisible by 3, the sum of its digits should be divisible by 3. 54,132 is an even number, so it is divisible by 2. 5 + 4 + 1 + 3 + 2 = 15, which is divisible by 3, so 54,132 is divisible by 3. Since 54,132 is divisible by both 2 and 3, it is divisible by 6.