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Is 78 divisible by every number?
78 is evenly divisible by 1, 2, 3, and 13.
What is 78 divisible by?
2, 3, 6, and 39
Is 45 divisible by 6?
No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.
If a number is divisible by both 2 and 3 then we can say the number is divisible by?
If a number is divisible by both 2 and 3, it is also divisible by 6. This is because 6 is the least common multiple of 2 and 3. Therefore, any number that meets the criteria of being divisible by both 2 and 3 will also be divisible by 6.
Is 90 divisible by 2 or 3?
The number 90 is divisible by both 2 and 3.
Is the number 78 is divisible by 2 and 3?
yes to both.
Is 78 divisible by every number?
78 is evenly divisible by 1, 2, 3, and 13.
What are divisible by 78?
All multiples of 78 are divisible by it. For example ( 78 X 2, 156) or (78 x 3 , 234) etc.
What is 78 divisible by?
2, 3, 6, and 39
Is 45 divisible by 6?
No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.
If a number is divisble by both 2 and 3 is it divisible by 6?
Any number that is divisible by both 2 and 3 is divisible by 6.
Is 1142 divisible by 2 and 3?
2 yes, 3 no.
If a number is divisible by both 2 and 3 then we can say the number is divisible by?
If a number is divisible by both 2 and 3, it is also divisible by 6. This is because 6 is the least common multiple of 2 and 3. Therefore, any number that meets the criteria of being divisible by both 2 and 3 will also be divisible by 6.
Is 90 divisible by 2 or 3?
The number 90 is divisible by both 2 and 3.
Is 432 divisible by 2 or 3?
432 is divisible evenly by both 2 and 3
How can you know if 6 is a factor of 78?
For a number to be divisible by 6, it has to be divisible by 2 and 3, because 2*3=6.In other words, we could divide the number we're factorising (78) by the prime factors of the number we're testing (6, which is 2*3). We start by dividing by 2, because we know 78 is even: 78/2=39. Then, we divide the new number by the other prime factor - 3. 39/3=13 13 is a whole number with no remainders, therefore we can say that 78 is divisible by 6, and therefore 6 is a factor of 78. (6*13=78)
What numbers are divisible by 2 and 3 and13?
78, 156, 234 and so on.
