yes because 6+3 =9 thats why 63 is divisble by 9
yes. it equals 7
3*21 = 63 so 63 is divisible by 3 7*9 = 63 so 63 is divisible by 7.
9
Yes, 63 is divisible by 3. You can determine this by adding the digits of 63 (6 + 3 = 9), and since 9 is divisible by 3, so is 63. Additionally, dividing 63 by 3 gives a quotient of 21 with no remainder, confirming its divisibility.
7 x 9 = 63 7 is a FACTOR of 63 9 is a FACTOR of 63 7 and 9 are even DIVISORS of 63 63 is a MULTIPLE of 7 and 9 63 is a PRODUCT of 7 and 9 63 is evenly DIVISIBLE by 7 or 9
7 and 9 are factors and divisors of 63 63 is a multiple and a product of 7 and 9 63 is divisible by 7 and 9
3*21 = 63 so 63 is divisible by 3 7*9 = 63 so 63 is divisible by 7.
9
Yes and the answer is 9 because 9*7 = 63
1, 3, 7, 9, 21, 63
63
7 x 9 = 63 7 is a FACTOR of 63 9 is a FACTOR of 63 7 and 9 are even DIVISORS of 63 63 is a MULTIPLE of 7 and 9 63 is a PRODUCT of 7 and 9 63 is evenly DIVISIBLE by 7 or 9
7 and 9 are factors and divisors of 63 63 is a multiple and a product of 7 and 9 63 is divisible by 7 and 9
Yes beacause 9 times 7 is 63
7 and 9 are factors and divisors of 63. 63 is a multiple and product of 7 and 9. 63 is divisible by 7 and 9.
9, 3, 63, 189
Yes they are. They are both divisible by 7. 14/2= 7 and 63/9=7
No, it is divisible by 7 and 9 along with 1, and 63 which don't count.