No because all integers are rational numbers
No it's 8, which is not irrational.
No.
It is rational
The square root of 128 is not an irrational number; it can be simplified. Specifically, (\sqrt{128} = \sqrt{64 \times 2} = \sqrt{64} \times \sqrt{2} = 8\sqrt{2}). Since (\sqrt{2}) is irrational, (\sqrt{128}) is also irrational.
No, 8 squared is not an irrational number. When you square 8, you get 64, which is a whole number and therefore a rational number. Rational numbers can be expressed as the quotient of two integers, and since 64 can be expressed as 64/1, it fits this definition.
irrational
No it's 8, which is not irrational.
No.
Rational
The square root of 64 is 8 which is a rational number
It is rational
rational
-- There's an infinite number of rational numbers. -- There's an infinite number of irrational numbers. -- There are more irrational numbers than rational numbers. -- The difference between the number of irrational numbers and the number of rational numbers is infinite.
Rational. √(1/64) = 1/√64 = 1/8
No. 64 can be represented as a fraction (ratio) of 64/1 .
The square root of 128 is not an irrational number; it can be simplified. Specifically, (\sqrt{128} = \sqrt{64 \times 2} = \sqrt{64} \times \sqrt{2} = 8\sqrt{2}). Since (\sqrt{2}) is irrational, (\sqrt{128}) is also irrational.
No, 8 squared is not an irrational number. When you square 8, you get 64, which is a whole number and therefore a rational number. Rational numbers can be expressed as the quotient of two integers, and since 64 can be expressed as 64/1, it fits this definition.