81 is divisible by 1, 3, 9, 27 and 81
No, 81 is not divisible by 4. In order for a number to be divisible by 4, the last two digits must be divisible by 4. In this case, the last two digits of 81 are 81 itself, which is not divisible by 4. Therefore, 81 is not divisible by 4.
it's only divisible by 3 243 divided by 3 is 81
its divisible by two
Yes, but not evenly, the quotient is 81 with a remainder of 2
"What is divisible by 81?" Any multiple of 81 is divisible by 81. For example, all of the following are divisible by 81: 81 = 1 x 81 162 = 2 x 81 243 = 3 x 81 324 = 4 x 81 and so on. ========================================= Did you mean to ask "What is 81 divisible by?" 81 is divisible by 1, 3, 9, 27, 81.
No.
Techcially all numbers are divisible by 81, however many would result in a decimal answer. If you mean how many numbers are divisible by 81 and have an integer answer, then it is "all multiples of 81" - e.g 81 x 2, 81 x 3 etc...81, 162, 243 and keep adding 81 forever.
81 is divisible by 1, 3, 9, 27 and 81
No, 81 is not divisible by 4. In order for a number to be divisible by 4, the last two digits must be divisible by 4. In this case, the last two digits of 81 are 81 itself, which is not divisible by 4. Therefore, 81 is not divisible by 4.
it's only divisible by 3 243 divided by 3 is 81
81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9. So 199 is the only one not divisible by 9.
its divisible by two
Any multiple of 81.
Yes, but not evenly, the quotient is 81 with a remainder of 2
No. 81 is not evenly divisible by six.
9 x 9 = 81