Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).
To simplify the expression (7p + 6q - 2p + q), combine like terms. First, combine the (p) terms: (7p - 2p = 5p). Next, combine the (q) terms: (6q + q = 7q). Therefore, the simplified expression is (5p + 7q).
7q+13 = 52 7q = 52-13 7q = 39 q = 39/7
The cube of the binomial ( (4k - 7q) ) can be calculated using the formula for the cube of a binomial, which is ( (a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3 ). Here, ( a = 4k ) and ( b = 7q ). Applying the formula, we get: [ (4k - 7q)^3 = (4k)^3 - 3(4k)^2(7q) + 3(4k)(7q)^2 - (7q)^3. ] This simplifies to: [ 64k^3 - 84k^2q + 147kq^2 - 343q^3. ]
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. Also use ^ to indicate powers (eg x-squared = x^2). Your question has no operator between -7q and 2.
To simplify the expression (2q + 10 + 7q), combine the like terms. The terms involving (q) are (2q) and (7q), which add up to (9q). Therefore, the simplified expression is (9q + 10).
This equation is linear, because neither variable symbol occurs to any power except the first.
With no equality sign the given expression is not an equation
Without an equality sign the given terms can't be considered to be an equation.
Neither because without an equality sign the given expressions can't be classed as an equation.
Solving by elimination: p = 3 and q = -2
5p-7q
To simplify the expression (7p + 6q - 2p + q), combine like terms. First, combine the (p) terms: (7p - 2p = 5p). Next, combine the (q) terms: (6q + q = 7q). Therefore, the simplified expression is (5p + 7q).
7q+13 = 52 7q = 52-13 7q = 39 q = 39/7
14p + 14q + p - 7q - 6p = 9p + 7q
welll 7xq = 7q..xq would be 7q squared
8 + 5p + 7q + 9 + 3p Reordering: 8 + 9 + 5p + 3p + 7q Combine like terms: 17 + 8p + 7q
The cube of the binomial ( (4k - 7q) ) can be calculated using the formula for the cube of a binomial, which is ( (a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3 ). Here, ( a = 4k ) and ( b = 7q ). Applying the formula, we get: [ (4k - 7q)^3 = (4k)^3 - 3(4k)^2(7q) + 3(4k)(7q)^2 - (7q)^3. ] This simplifies to: [ 64k^3 - 84k^2q + 147kq^2 - 343q^3. ]