Mathematically, the question is as solid as smoke.
The problem is: What does "and" mean ?
Without a mathematical operation specified, we don't know how the binomial and monomial
may affect each other, or what the result may be.
Having a binomial "and" a monomial, all we have so far is two algebraic expressions written down
on our paper. They're not equal to anything except a binomial 'and' a monomial, until we get some
clear instructions on how they're supposed to be manipulated.
Yes.
No. A counter-example proves the falsity: Consider the two binomials (x + 2) and (x - 2). Then (x + 2)(x - 2) = x2 - 2x + 2x - 4 = x2 - 4 another binomial.
Use the continuity correction when using the normal distribution to approximate a binomial distribution to take into account the binomial is a discrete distribution and the normal distribution is continuous.
Always
sometimes
no, because some examples are: (a-2)(a+2) = a^2-4 (binomial) & (a+b)(c-d) = ac-ad+bc-db (polynomial) but can 2 binomials equal to a monomial?
Yes.
This is related to the fact that the square of both a positive and a negative number is always positive. The last term is simply the square of the second term, in the original binomial.
Is sometimes possible, but not always.
It is always 1
No. A counter-example proves the falsity: Consider the two binomials (x + 2) and (x - 2). Then (x + 2)(x - 2) = x2 - 2x + 2x - 4 = x2 - 4 another binomial.
yes
By convention the binomial Latin names are always italicized.
philip aidan kuan, the scientist proved that trinomialis good
Use the continuity correction when using the normal distribution to approximate a binomial distribution to take into account the binomial is a discrete distribution and the normal distribution is continuous.
Sometimes Always was created in 1994-07.
To factor a trinomial in the form ax2 + bx + c, where a does not equal 1, the easiest process is called "factoring by grouping". To factor by grouping, you must change the trinomial into an equivalent tetranomial by rewriting the middle term (bx) as the sum of two terms. There is a specific way to do this, as demonstrated in the example.Take the quadratic trinomial 5x2 + 11x + 21. Find the product of a and c, or 5*2 = 10.2. Find factors of ac that when added together give you b, in this case 10 and 1.3. Rewrite the middle term as the sum of the two factors (5x2 + 10x + x + 2).4. Group terms with common factors and factor these groups.5x2 + x + 10x + 2x(5x + 1) + 2(5x + 1)5. Factor the binomial in the parentheses out of the whole polynomial, leaving you with the product of two binomials. 5x2 + 11x + 2 = (x + 2)(5x + 1)Notes:1. The same process is done if there are any minus signs in the trinomial, just be careful when factoring out a negative from a positive or vice versa.2. If you have a tetranomial on its own, you can skip the rewriting process and just factor the whole polynomial by grouping from the start.3. As in factoring any polynomial, always factor out the GCF first, then factor the remaining polynomial if necessary.4. Always look for patterns, like the difference of squares or square of a binomial, while factoring. It will save a lot of time.