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Is sometimes possible, but not always.

Q: To write a polynomial as the product of 1 monomial factors and 2 prime factors with at least two terms?

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They don't. At least, not for their nursing work.

The polynomial P(x)=(x-3)(x-0)(x+3)(x-1) is of the fourth degree.

3y2-5xyz yay i figured it out!!!!

Prime numbers have only two factors: one and themselves. By definition, your product would have more than that: one, the product and at least the two numbers that created the product. It has to be composite.

First, I determined the least common multiple to see how many factors it had. The least common multiple is the product of the two numbers divided by the greatest common factor, which is 35 x 77 ÷ 7 = 385. The factors of 385 are 1, 5, 7, 11, 35, 55, 77, and 385. There are 8 factors, so this number satisfies the requirements.

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Factor

Any polynomial in which there are at least two co-prime coefficients will have 1 as the greatest monomial factor.

It's the same process as composite numbers. Factor them. Combine the factors, eliminating duplicates. If they have no common factors, the LCM is their product.

You need at least two terms to find an LCM.

Since the question did not specify a rational polynomial, the answer is a polynomial of degree 3.

The LCM for 1,2,3,4,5,6 is 60.

You forgot to copy the polynomial. However, the Fundamental Theorem of Algebra states that every polynomial has at least one root, if complex roots are allowed. If a polynomial has only real coefficients, and it it of odd degree, it will also have at least one real solution.

At least two.

No. Factors combine in multiplication to create a product.

When there are no common factors other than 1.

If the prime factorizations have no factors in common, the LCM is the product of them.

The LCM of 3s and s^2 is 3s^2