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Q: To write a polynomial as the product of 1 monomial factors and 2 prime factors with at least two terms?

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They don't. At least, not for their nursing work.

The polynomial P(x)=(x-3)(x-0)(x+3)(x-1) is of the fourth degree.

3y2-5xyz yay i figured it out!!!!

Prime numbers have only two factors: one and themselves. By definition, your product would have more than that: one, the product and at least the two numbers that created the product. It has to be composite.

First, I determined the least common multiple to see how many factors it had. The least common multiple is the product of the two numbers divided by the greatest common factor, which is 35 x 77 ÷ 7 = 385. The factors of 385 are 1, 5, 7, 11, 35, 55, 77, and 385. There are 8 factors, so this number satisfies the requirements.

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Factor

Any polynomial in which there are at least two co-prime coefficients will have 1 as the greatest monomial factor.

It's the same process as composite numbers. Factor them. Combine the factors, eliminating duplicates. If they have no common factors, the LCM is their product.

The LCM for 1,2,3,4,5,6 is 60.

You need at least two terms to find an LCM.

Since the question did not specify a rational polynomial, the answer is a polynomial of degree 3.

At least two.

You forgot to copy the polynomial. However, the Fundamental Theorem of Algebra states that every polynomial has at least one root, if complex roots are allowed. If a polynomial has only real coefficients, and it it of odd degree, it will also have at least one real solution.

At least one of the factors of an even number must be even, because the product of odd factors is always odd.

If there are no prime factors in common, the LCM will be the product. If there are prime factors in common, the LCM will be less than the product.

You need at least two terms to find a GCF.

Since there are no common factors, the least common multiple is the product of the two.

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