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If you multiply 2 binomials together will you always get a trinomial as a result?
Wiki User
∙ 11y ago
philip aidan kuan, the scientist proved that trinomialis good
Wiki User
∙ 11y ago
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Will the product of two binomials always equal a trinomial?
no, because some examples are: (a-2)(a+2) = a^2-4 (binomial) & (a+b)(c-d) = ac-ad+bc-db (polynomial) but can 2 binomials equal to a monomial?
What two numbers can you multiply to 30 and add up to -17?
13
How many square feet are in a property which is 70 X 100?
If these numbers are measurements in feet, multiply them together: 7000 sq ft. If not convert each one to feet and then multiply. Always quote units, otherwise people have to guess them.
How do factor a trinomial expression with a leading coefficient not equal to 1?
To factor a trinomial in the form ax2 + bx + c, where a does not equal 1, the easiest process is called "factoring by grouping". To factor by grouping, you must change the trinomial into an equivalent tetranomial by rewriting the middle term (bx) as the sum of two terms. There is a specific way to do this, as demonstrated in the example.Take the quadratic trinomial 5x2 + 11x + 21. Find the product of a and c, or 5*2 = 10.2. Find factors of ac that when added together give you b, in this case 10 and 1.3. Rewrite the middle term as the sum of the two factors (5x2 + 10x + x + 2).4. Group terms with common factors and factor these groups.5x2 + x + 10x + 2x(5x + 1) + 2(5x + 1)5. Factor the binomial in the parentheses out of the whole polynomial, leaving you with the product of two binomials. 5x2 + 11x + 2 = (x + 2)(5x + 1)Notes:1. The same process is done if there are any minus signs in the trinomial, just be careful when factoring out a negative from a positive or vice versa.2. If you have a tetranomial on its own, you can skip the rewriting process and just factor the whole polynomial by grouping from the start.3. As in factoring any polynomial, always factor out the GCF first, then factor the remaining polynomial if necessary.4. Always look for patterns, like the difference of squares or square of a binomial, while factoring. It will save a lot of time.
When you multiply by 0 the product is always?
The product would always be 0.
Will the product of two binomials always equal a trinomial?
no, because some examples are: (a-2)(a+2) = a^2-4 (binomial) & (a+b)(c-d) = ac-ad+bc-db (polynomial) but can 2 binomials equal to a monomial?
Will the product of two binomials after combining like terms always be trinomial?
No. A counter-example proves the falsity: Consider the two binomials (x + 2) and (x - 2). Then (x + 2)(x - 2) = x2 - 2x + 2x - 4 = x2 - 4 another binomial.
How do you multiply a fraction?
Multiply the numerators together. Multiply the denominators together. Reduce, if possible. The answer when multiplying fractions together will always be lower than either.
When you multiply two prime numbers together you always get an even number?
3 x 5 = 15
What two numbers can you multiply to 30 and add up to -17?
13
How many square feet are in a property which is 70 X 100?
If these numbers are measurements in feet, multiply them together: 7000 sq ft. If not convert each one to feet and then multiply. Always quote units, otherwise people have to guess them.
When you times by 5 the answer is always even?
if you multiply an even number by 5 then it will always end in 0 but if you multiply an odd number by 5 then it will always end in 5.
How do factor a trinomial expression with a leading coefficient not equal to 1?
To factor a trinomial in the form ax2 + bx + c, where a does not equal 1, the easiest process is called "factoring by grouping". To factor by grouping, you must change the trinomial into an equivalent tetranomial by rewriting the middle term (bx) as the sum of two terms. There is a specific way to do this, as demonstrated in the example.Take the quadratic trinomial 5x2 + 11x + 21. Find the product of a and c, or 5*2 = 10.2. Find factors of ac that when added together give you b, in this case 10 and 1.3. Rewrite the middle term as the sum of the two factors (5x2 + 10x + x + 2).4. Group terms with common factors and factor these groups.5x2 + x + 10x + 2x(5x + 1) + 2(5x + 1)5. Factor the binomial in the parentheses out of the whole polynomial, leaving you with the product of two binomials. 5x2 + 11x + 2 = (x + 2)(5x + 1)Notes:1. The same process is done if there are any minus signs in the trinomial, just be careful when factoring out a negative from a positive or vice versa.2. If you have a tetranomial on its own, you can skip the rewriting process and just factor the whole polynomial by grouping from the start.3. As in factoring any polynomial, always factor out the GCF first, then factor the remaining polynomial if necessary.4. Always look for patterns, like the difference of squares or square of a binomial, while factoring. It will save a lot of time.
How do you factor q2-7q plus 12?
1. When factoring first always look for a GCF (greatest common factor). If each term has a greatest common factor, factor it out in from using parenthesis first. This problem does not have a GCF. 2. Next, since this is a trinomial, many times we can factor it down using backwards FOIL (First, Outter, Inner, Last). 3. To do this always put down two sets of parenthesis. (we do this because we are looking to factor into two binomials) ( )( ) 4. Next we complete the fist term in each set of parenthesis. The first term is simply going to be the variable we are using in the problem. In this problem the variable is q. (q )(q ) 5. Then find the factors of the last term (+12) in which the sum is equal to the coefficient of the middle term (-7). These factors are -3 and -4. 6. Complete the factoring by putting these factors into the second part of the parenthesis. (q - 3)(q - 4) * If you want to make sure you are correct, multiply you answer out and see if you get the same trinomial you started with.
How do you multiply by the reciprocal?
You don't need to. When you multiply anything by its reciprocal, the answer is always ' 1 '.
Why when you multiply an odd number by a even does it always equal a even?
When you multiply an odd number by an even number, you are essentially adding an even number of odd numbers together. Since adding an even number of odd numbers will always result in an even number, the product will be even.
When you multiply by 0 the product is always?
The product would always be 0.
