(8*15)-16=104 diagonals in a 16 sided polygon.
It is: 8-2 = 6 triangles
A polygon with 6 sides is a hexagon and a polygon with 8 sides is an octagon
If the polygon has n sides, the sum of its interior angles is 180*(n - 2) degrees. [Whether the polygon is regular or not is irrelevant] So, 180*(n - 2) = 1080 (n - 2) = 6 n = 8 Then number of diagonals = n*(n - 3)/2 = 8*5/2 = 20
An 8 sided octagon has 20 diagonals according to the formula 0.5*(n^2 -3n) whereas n is the number of sides of the polygon.
(8*15)-16=104 diagonals in a 16 sided polygon.
A regular octogon (8 sides) has 20 diagonals. An irregular octogon also has 20 diagonals, but only if all its points point outwards.
It is: 8-2 = 6 triangles
Sides: 8 Diagonals : 20
There are 8 sides in the polygon with 8 sides (an octagon).
20 diagonals For any n-sides polygon, the formula for the number of diagonals is (n/2) x (n-3), so for an octagon it is (8/2) x (8-3) = 4 x 5 = 20.
A diagonal line of a polygon is a line that joins any two vertices not already joined by a side. A polygon with n sides has n(n-3)/2 diagonals → an octagon has 8(8-3)/2 = 8 × 5 ÷ 2 = 20 diagonals
A polygon with 6 sides is a hexagon and a polygon with 8 sides is an octagon
28
A polygon with 8 sides is an octagon.
4...
If the polygon has n sides, the sum of its interior angles is 180*(n - 2) degrees. [Whether the polygon is regular or not is irrelevant] So, 180*(n - 2) = 1080 (n - 2) = 6 n = 8 Then number of diagonals = n*(n - 3)/2 = 8*5/2 = 20