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A normal convex polygon cannot have 15 diagonals.

If it has n sides, it has n*(n-3)/2 diagonals and this is equal to 15 if n = 7.18. However, it is not possible for a polygon to have a fractional side.

Q: Is a polygon with 8 sides have 15 diagonals?

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(8*15)-16=104 diagonals in a 16 sided polygon.

It is: 8-2 = 6 triangles

A polygon with 6 sides is a hexagon and a polygon with 8 sides is an octagon

If the polygon has n sides, the sum of its interior angles is 180*(n - 2) degrees. [Whether the polygon is regular or not is irrelevant] So, 180*(n - 2) = 1080 (n - 2) = 6 n = 8 Then number of diagonals = n*(n - 3)/2 = 8*5/2 = 20

Defining a diagonal as any two vertices that are not connected by an edge (non-adjacent) of the polygon, you can determine the amount of diagonals using the following formulas = sides in polygon(s*(s-3))/2So,(3*(3-3))/2 = 0(4*(4-3))/2 = 2(5*(5-3))/2 = 5(6*(6-3))/2 = 9(7*(7-3))/2 = 14(8*(8-3))/2 = 20(9*(9-3))/2 = 27(10*(10-3))/2 = 35(11*(11-3))/2 = 44So, the polygon would have to have somewhere between 10 and 11 sides. Since a polygon can not have fractional amount of sides, no polygon exists that has 42 diagonals.

Related questions

(8*15)-16=104 diagonals in a 16 sided polygon.

A regular octogon (8 sides) has 20 diagonals. An irregular octogon also has 20 diagonals, but only if all its points point outwards.

It is: 8-2 = 6 triangles

20 diagonals For any n-sides polygon, the formula for the number of diagonals is (n/2) x (n-3), so for an octagon it is (8/2) x (8-3) = 4 x 5 = 20.

A diagonal line of a polygon is a line that joins any two vertices not already joined by a side. A polygon with n sides has n(n-3)/2 diagonals → an octagon has 8(8-3)/2 = 8 × 5 ÷ 2 = 20 diagonals

Sides: 8 Diagonals : 20

There are 8 sides in the polygon with 8 sides (an octagon).

A polygon with 6 sides is a hexagon and a polygon with 8 sides is an octagon

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A polygon with 8 sides is an octagon.

If the polygon has n sides, the sum of its interior angles is 180*(n - 2) degrees. [Whether the polygon is regular or not is irrelevant] So, 180*(n - 2) = 1080 (n - 2) = 6 n = 8 Then number of diagonals = n*(n - 3)/2 = 8*5/2 = 20

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