Yes. You should be able to multiply any number's multiple's into itself.
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All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.
yes, every multiple of 9 is a multiple of 3, but that doesn't cover all of them ...there are more multiples of 3 besides those.
Itself and any multiples of 9
Because they are multiples of 5. All multiples of 5 have 5 as a factor, which means they are divisible by 5.
All of its multiples are.