The differential of the sine function is the cosine function while the differential of the cosine function is the negative of the sine function.
The inverse of the cosine is the secant.
I was not aware that the cosine function was in fashion!The range, on the other hand, is [-1, 1].
The argument of the cosine function must be (2pi/3)*x radians
Tangent = sine/cosine provided that cosine is non-zero. When cosine is 0, then tangent is undefined.
Yes they are. Both have a a period of 2 pi
because sine & cosine functions are periodic.
The differential of the sine function is the cosine function while the differential of the cosine function is the negative of the sine function.
Cosine is a trigonometrical function.
-1<cosine<1
The inverse of the cosine is the secant.
The Y-Intercept of the cosine function is X = 0, Y = cosine(0) = 1.
Yes. The cosine function is continuous. The sine function is also continuous. The tangent function, however, is not continuous.
The cosine function, like all of the trigonometric functions, is periodic about the rotation around a circle. Since the cosine is defined as the adjacent/hypotenuse of a right triangle, you can clearly see that its value can never be greater than one or less than -1 since the hypotenuse is always longer than the adjacent side. It turns out that, indeed, the cosine's range is from -1 to 1, written [-1,1].
False; the cosine function is an even function as cos(-x) = -cos(x).
I was not aware that the cosine function was in fashion!The range, on the other hand, is [-1, 1].
The argument of the cosine function must be (2pi/3)*x radians