Q: Is f(x) shifted upward a units?

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The result depends on how the function f() is defined. Simply copy the function definition, replacing every "x" (assuming the function is defined in terms of "x") by "x+5".

y = -y implies the first line is y = 0 or the x axis. Shifted up 4 units, it becomes the line y = 4.

It will be f(x+4).

The second graph is shifted upwards by 4 units.

f(x)+a : shift upward a units f(x)-a : shift downward a units f(x+a) : shift left a units f(x-a) : shift right a units -f(x) : reflection across the x-axis f(-x) : mirror; reflection across the y-axis

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Can someone please help me???

if a figure is shifted 3 units to the right, you add to the coordinate

The result depends on how the function f() is defined. Simply copy the function definition, replacing every "x" (assuming the function is defined in terms of "x") by "x+5".

To shift a funcion (or its graph) down "a" units, you subtract "a" from the function. For example, x squared gives you a certain graph; "x squared minus a" will give you the same graph, but shifted down "a" units. Similarly, you can shift a graph upwards "a" units, by adding "a" to the function.

y = -y implies the first line is y = 0 or the x axis. Shifted up 4 units, it becomes the line y = 4.

it is the same as a sin function only shifted to the left pi/2 units

(4,1)

The graph of is shifted 3 units down and 2 units right. Which equation represents the new graph?

It will be f(x+4).

The second graph is shifted upwards by 4 units.

The standard form of the quadratic function in (x - b)2 + c, has a vertex of (b, c). Thus, b is the units shifted to the right of the y-axis, and c is the units shifted above the x-axis.

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