No because the 3 sides of an equilateral triangle are equal in length
No, it is not possible to draw a triangle with sides of 150 cm, 10 cm, and 10 cm. According to the triangle inequality theorem, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 10 cm + 10 cm is not greater than 150 cm.
So?
It is a right angle triangle and its largest angle is 90 degrees
8.66cm; noIf you have heard of a 30-60-90 triangle with sides in the ratio of 1 to sqrt(3) to 2, then this should be easy:Draw an equilateral triangle with one side at the bottom. Find the middle of the base, and draw a vertical line to divide the triangle in two. (Sorry, I can't draw this!) Now suppose the length of each side of the equilateral triangle is 2 units. You have divided the base into two parts each with a length of 1.Each smaller triangle is a right triangle with hypotenuse 2 and one side 1 unit long. the 3rd side is the altitude of the equilateral triangle, call it h. Pythagoras tells us that 12 + h2 = 22 1 + h2 = 4 h2 = 4-1 = 3 h = sqrt(3).The height of an equilateral triangle is always sqrt(3) times half the length of a side. This comes out to about 0.866 times the length of a side, so if the side is 10cm long, the height will be 8.66cm.(The height isn't the same as one of the sides, it's about 13/15 of it.)
The base is an equilateral triangle and so the volume works out as follows:- 0.5*122*sin(60)*10 = 623.538 cubic cm to 3 decimal places
Size or internal angles?
if it is a scalene triangle yes scalene triangle have no congruent sides and angles
No, it is not possible to draw a triangle with sides of 150 cm, 10 cm, and 10 cm. According to the triangle inequality theorem, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 10 cm + 10 cm is not greater than 150 cm.
So?
If the sides are 10cm, 17cm and 21cm, the three angles are approx 28, 53 and 99 degrees. It is an obtuse angled triangle.
It is a right angle triangle and its largest angle is 90 degrees
200 sq. cm.
8.66cm; noIf you have heard of a 30-60-90 triangle with sides in the ratio of 1 to sqrt(3) to 2, then this should be easy:Draw an equilateral triangle with one side at the bottom. Find the middle of the base, and draw a vertical line to divide the triangle in two. (Sorry, I can't draw this!) Now suppose the length of each side of the equilateral triangle is 2 units. You have divided the base into two parts each with a length of 1.Each smaller triangle is a right triangle with hypotenuse 2 and one side 1 unit long. the 3rd side is the altitude of the equilateral triangle, call it h. Pythagoras tells us that 12 + h2 = 22 1 + h2 = 4 h2 = 4-1 = 3 h = sqrt(3).The height of an equilateral triangle is always sqrt(3) times half the length of a side. This comes out to about 0.866 times the length of a side, so if the side is 10cm long, the height will be 8.66cm.(The height isn't the same as one of the sides, it's about 13/15 of it.)
The base is an equilateral triangle and so the volume works out as follows:- 0.5*122*sin(60)*10 = 623.538 cubic cm to 3 decimal places
one side equals 5 another equals 4 and the last is 1 (a=bh/2)
a is one of the equal sides of the iscosceles triangle b is the base perimeter is a + a + b = 46cm a = b + 5cm subsitute a for b + 5cm in the perimeter equation b + 5cm + b + 5cm + b = 46cm This simplifies down to 3b + 10cm = 46cm subtract 10cm from both sides of the equation 3b + 10cm - 10cm = 46cm - 10cm 3b = 36cm Then divide each side of the equation by 3 3b ÷ 3 = 36cm ÷ 3 b = 12cm Subsitute b back into a = b +5cm a = 12cm + 5cm a = 17cm So you have 2 sided with the length of 17cm and the base with the length of 12cm
No because an isosceles triangle has 2 equal sides and 2 equal interior angles with another angle and the 3 angles add up to 180 degrees