Generally speaking, yes.
But, if you want to be pedantic about it, the answer must be NO. You cannot see accurately enough. Are you eyes good enough to go down to a micrometre? A nanometre? The width of an atom? The Planck length? NO. You cannot design an instrument that can be accurate below Planck's length. So, in the final analysis, you can't.
Yes. It does.
Segment: The length of one side of an object only measuring the length of that individual side. For Example: Line Segment AB measures 2 in.
The dimensions of any objects we touch, feel, and use in our every day life in 3 dimensional. When we say dimension we mean... How long is it? How high is it? How wide is it? Long in maths terms is length high in maths terms is height wide in math terms is width or depth When we draw on peices of paper it become 2 dimensional. On paper we can only draw length and height. You can not physically draw depth. Depth means it is going into the paper and this is not physically possible. Extremely talented artists and give an illision like it is 3-D but it really is still simply 2-D. To actually draw 2-D shapes get a piece of paper. Draw a square. That square is 2-D shape. Draw a rectangle. That rectangle is in 2-D. Do this for all the shapes you can think of. Make sure to draw the proper length and height.
you draw it with 2 sides of the same length and 1 that isn't the same as the others
Do I have a compass to use or not ? It's not clear from your question, but since you mentioned it at the end of the question, I'll assume that I do have a compass, and in that case, I only need one straight-edge. 1). Plant the compass on one end of the line segment, open it to more than half the length of the segment, draw a long arc that crosses the segment. 2). Keep the same opening, pick up the compass. 3). Plant the compass on the other end of the segment, draw another long arc that crosses the segment. 4). Sell the compass. 5). The two arcs intersect at two points on opposite sides of the segment. With your straight edge, draw a line between these two points. That line is the perpendicular bisector of the original segment.
3.9 and 2.6
what about such a line segment? the length of such a segment is called the radius. the area of the circle is pi*the length of this segment squared the circumference is 2*pi*the length of this segment
The length of the line segment is the square root of (x1-x2)2+(y1-y2)2
if the segment is the whole length of the circle divide it by 2
multiply the chord length and radius and divide by 2
If the midpoint of a horizontal line segment with a length of 8 is (3, -2), then the coordinates of its endpoints are (6, -2) and (0, -4).
Yes. All you need is a square whose sides are sqrt(32) = 4*sqrt(2) in length. You might try and argue that 4*sqrt(2) is an irrational number and so cannot be calculated exactly so it is not possible to draw a side of length 4*sqrt(2). Faulty argument. Draw a 4*4 square. Easy enough! The diagonal of this square has length sqrt(32) = 4*sqrt(2). So now you have a line of the required length.
Yes. It does.
Segment: The length of one side of an object only measuring the length of that individual side. For Example: Line Segment AB measures 2 in.
If you mean: (2, 5) and (2, 8) then the length works out as 3 units
It is 3 units long.
10