multiply the chord length and radius and divide by 2
The radial length equals the chord length at a central angle of 60 degrees.
There must be an equilateral triangle within the sector of the circle and so:- Area of sector: 60/360*pi*12*12 = 75.39822369 Area of triangle: 0.5*12*12*sin(60 degrees) = 62.35382907 Area of segment: 75.39822369-62.35382907 = 13.04439462 or about 13 square units
Assuming you know c (not Arc ZX) and m then the formula would be: r = (m² + ¼c²)/2m if all you need to know is the radius of an arc, and you have the base length and rise, the formula would be: radius = (rise2 + 1/2 width2) / 2 x rise
I assume that you want to divide it into three equal "pie slices".If you have the location of the center of the circle, and are allowed to use a protractor (or other angle-measuring device), then you draw a radial line segment from the center to the circle, then another radial line segment at a 120° and to the first radial line segment, and final radial line segment at a further 120° angle.If you have only the circle, a straight-edge, and a compass, then you must first locate the center of the circle. Draw two cords, Use the compass to construct bisecting perpendicular lines for each chord. These bisecting perpendicular lines will meet at the center of the circle.If you now draw a chord equal in length to the radius, and radial lines from each of its ends, then that gives you a "pie slice" that is one sixth of the circle! So if you draw a second chord where the first ends, you have a "pie slice" that is one third of the circle.So you could draw five chord, each the length of the radius, each starting where the previous ended, and draw radial lines through every second chord-end. Or you could use the first two chords to find the length of a chord which corresponded to a third of the circle.(Actually, you don't really have to draw any of these chords, you just need to mark their end-points as you go along.)
double the length
Assume that the height of the segment is h, the chord length is c and the radius is r then: r2=(r-h)2+(c/2)2 (We join two radii to the two ends of the chord then extend the height of the segment to the center of the circle in which the segment is inscribed so this height will bisect the chord and you use the pythagorean theorem to find the radius)
If you are given a chord length of a circle, unless you are given more information about the chord, you can not determine what the radius of the circle will be. This is because the chord length in a circle can vary from a length of (essentially) 0, up to a length of double the radius (the diameter). The best you can say about the radius if given the chord length, is that the length of the radius is at least as long has half half the chord length.
If the central angle is 70 and the radius is 8cm, how do you find out the chord lenght?
Unless the chord is the diameter, there is no way to measure the radius of the circle. This is because the radius is in no way dependent on chord length since circles have infinite amount of chord lengths.
If the radius is 8cm and the central angle is 70, how do yu workout the chord lenght?
The longest chord in a circle is its diameter and halve of this is its radius.
you have a triangle formed by the radius on 2 and the chord on the other. the angle in that triangle that is opposite the chord, find its measure in radians take that measure (in radians) and multiply it by the radius to get the arc length
if the segment is the whole length of the circle divide it by 2
The solution depends on the information supplied. Basically, you find the area of the sector containing the segment and then deduct the area of the triangle formed by the chord and the two radii enclosing the sector. If you are given the radius(r) of the circle and the height(h) then construct a radius that is perpendicular to and bisects the chord. This will create two congruent triangles which together form the main triangle. Using Pythagoras enables the half-chord length to be calculated as the hypotenuse is r and the height (also the length of the third side) is r-h. With this information the full chord length can be established and thus the area of the main triangle. Using sine or cosine methods enables the sector angle at the centre to be calculated and thus the sector area. Simple subtraction produces the area of the segment. If you are given the radius and the chord(c) length then the construction referred to above enables the height of the main triangle to be calculated and a similar process will generate the area of that triangle and the sector area. This, in turn, will enable the segment area to be determined.
r = known radius x = known arc length --------------------------- C (circumference of circle) = 2 * PI * r A (angle of chord in degrees) = x / C * 360 L (length of chord) = r * sin(A/2) * 2
The length of a chord = pi*r*x/180 where x is the angle subtended. = pi*5*80/180 = 6.98 cm
Imagine if you will a circle with a chord drawn through it and a line running from the center of that chord to the center of the circle. That line is necessarily perpendicular to the chord. This means you have a right triangle whose hypotenuse is the radius of the circle. The radius is thus given by: r = sqrt{(1/2 chord length)^2 + (length of perpendicular line)^2} The actual formula to find the radius is as follows: r= C squared/8a + a/2, where C is the chord length, and a is the distance from center point of the chord to the circle , and a and C form an angle of 90 degrees. the entire formula before simplification is r = sqrt {(1/2 C)^2 + (r-a)^2}