Their sum is 15.
111, 112 and 113.
Yes, the product of any three consecutive numbers is divisible by 6. This is because among any three consecutive integers, at least one of them is even (ensuring divisibility by 2), and at least one of them is divisible by 3. Since 6 is the product of 2 and 3, the product of any three consecutive numbers is therefore divisible by 6.
-7
Any two consecutive numbers must comprise one odd and one even number, so their product must be even. Any three consecutive numbers must include two consecutive numbers so the result still applies.
No.
No. Every third consecutive natural number is divisible by 3.
111, 112 and 113.
0,6,18,36,60,90,126,168, etc
Yes, the product of any three consecutive numbers is divisible by 6. This is because among any three consecutive integers, at least one of them is even (ensuring divisibility by 2), and at least one of them is divisible by 3. Since 6 is the product of 2 and 3, the product of any three consecutive numbers is therefore divisible by 6.
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
-7
9240 is the product of the three consecutive integers 20, 21, and 22.
Any two consecutive numbers must comprise one odd and one even number, so their product must be even. Any three consecutive numbers must include two consecutive numbers so the result still applies.
No.
If you define a rectangular number as a number which is the product of two consecutive integers, none of them qualify.
The three consecutive numbers whose sum and product are the same are 1, 2, and 3.
four