If: k+3=-3 Then: k=-3-3 k=-6
k = -3; factors are (9x + 3)(x - 1)
j=-3 and k=2
As an algebraic expression it is: 3+14k
c-a=k
If: k+3=-3 Then: k=-3-3 k=-6
One triplet (k) and two pairs (h and number). 3j has no like term.
k + 5k = 6k 2 x 3 x k
3k-1=k+2 2k=3 k=3/2=1.5
k = -3; factors are (9x + 3)(x - 1)
j=-3 and k=2
As an algebraic expression it is: 3+14k
K. F. Riley has written: 'Mathematical methods for physics and engineering' -- subject(s): Mathematical analysis, Mathematical physics, Engineering mathematics
c-a=k
K/3 + k/4 = 1 LCD=12 *divide lcd by denominator* K(4) + K(3) = 12(1) 4k + 3k = 12 7k = 12 k=12/7
Taking all terms and conditions into consideration a quadratic equation can be finally formed as such that 3k^2 +8k +4 = 0 whose solutions are k = -2/3 or k = -2 Check: 3(-2/3)^2 +8(-2/3) +4 = 0 Check: 3(-2)^2 +8(-2) +4 = 0
Print "Type the upper limit (n) ?" Input n K = -1 WHILE K < = n K = K + 2 Sum = Sum + K WEND Print "The sum of all odd numbers up to "; n; "is "; Sum