-14
If: k+3=-3 Then: k=-3-3 k=-6
k = -3; factors are (9x + 3)(x - 1)
j=-3 and k=2
Taking all terms and conditions into consideration a quadratic equation can be finally formed as such that 3k^2 +8k +4 = 0 whose solutions are k = -2/3 or k = -2 Check: 3(-2/3)^2 +8(-2/3) +4 = 0 Check: 3(-2)^2 +8(-2) +4 = 0
-14
==> 3k+14=k ==>3k-k=-14 ==>2k=-14 ==>k=-7 ans...
If: k+3=-3 Then: k=-3-3 k=-6
17
If: 12k = 84 then k = 7
One triplet (k) and two pairs (h and number). 3j has no like term.
(k*m)3 = k3*m3
k = 14/43
k + 5k = 6k 2 x 3 x k
3k-1=k+2 2k=3 k=3/2=1.5
m+6n
k = -3; factors are (9x + 3)(x - 1)