Yes. Logarithms to the base 10 are called common logarithms, and 2 is the correct common logarithm for 100.
log(36,200) = 4.558709 (rounded)log[log(36,200)] = 0.658842 (rounded)
Logarithms can be taken to any base. Common logarithms are logarithms taken to base 10; it is sometimes abbreviated to lg. Natural logarithms are logarithms taken to base e (= 2.71828....); it is usually abbreviated to ln.
It is because the logarithm function is strictly monotonic.
Common
The logarithm to the base 10 of 100 is 2, because 102 = 100.
y = 10 y = log x (the base of the log is 10, common logarithm) 10 = log x so that, 10^10 = x 10,000,000,000 = x
Natural log Common log Binary log
"Log" is not a normal variable, it stands for the logarithm function.log (a.b)=log a+log blog(a/b)=log a-log blog (a)^n= n log a
log(36,200) = 4.558709 (rounded)log[log(36,200)] = 0.658842 (rounded)
log base 10 x = logx
Logarithms can be taken to any base. Common logarithms are logarithms taken to base 10; it is sometimes abbreviated to lg. Natural logarithms are logarithms taken to base e (= 2.71828....); it is usually abbreviated to ln.
It is because the logarithm function is strictly monotonic.
Common
The logarithm to the base 10 of 100 is 2, because 102 = 100.
The value of log 500 depends on the base of the logarithm. If the base is 10 (common logarithm), then log 500 is approximately 2.69897. If the base is e (natural logarithm), then log_e 500 is approximately 6.2146. The logarithm function is the inverse of exponentiation, so log 500 represents the power to which the base must be raised to equal 500.
The 'common' log of 4 is 0.60206 (rounded) The 'natural' log of 4 is 1.3863 (rounded)
logarithm of 100 = 2. If there is not a subscript number on your log, you assume it to be 10. In other words, the little subscript would be the base if you were raising it to a power, and the big number is the answer of the power. For example, log (base 10) 100 = 2 because 10 (the base) raised to a power of 2 (the log answer) = 100 (the number you just took the log of.)