No, but any parabola can be transformed into the form y = x^2.
An x2 parabola will always have one vertex, but depending on the discriminant of the function (b2-4ac) the parabola will either have 2 roots (it crosses the x-axis twice), 1 repeating root (the parabola meets the x-axis at a single point), or no real roots (the parabola doesn't meet the x-axis at all)
An equation for a parabola always has some type of irregular variable, usually a squared variable or higher.
Nope. False.
No. It can also be a circle, ellipse or hyperbola.
No, if the vertex of the parabola is (0, 0) it will only have one x intercept. The parabola might have zero x intercepts as well. For example: Y= x^2 + 1 would never touch the x line.
upward
10
dsvcvWv
It is the bisector of any 2 parallel chords drawn to the parabola. It is always parallel to the axis of the parabola.
An x2 parabola will always have one vertex, but depending on the discriminant of the function (b2-4ac) the parabola will either have 2 roots (it crosses the x-axis twice), 1 repeating root (the parabola meets the x-axis at a single point), or no real roots (the parabola doesn't meet the x-axis at all)
Yes, it is.
If you're looking to factor it, you can do it like so: d2ydx2 - yx2 = d3yx2 - yx2 = yx2(d3 - 1)
An equation for a parabola always has some type of irregular variable, usually a squared variable or higher.
The domain of a parabola is always all real numbers because the domain represents the possible x values. The x values are shown on the horizontal axis or x axis. Because, in a parabola, the 2 sides of the parabola go infinitely in a positive or negative direction, there is always a y value for any x value that u plug in to the equation.
No. It can also be a circle, ellipse or hyperbola.
Nope. False.
No, if the vertex of the parabola is (0, 0) it will only have one x intercept. The parabola might have zero x intercepts as well. For example: Y= x^2 + 1 would never touch the x line.