To graph the equation ( y = x^2 ), first recognize that it represents a parabola opening upwards. Plot key points, such as ( (0, 0) ), ( (1, 1) ), ( (-1, 1) ), ( (2, 4) ), and ( (-2, 4) ). Connect these points smoothly, ensuring the curve is symmetric about the y-axis. The vertex of the parabola is at the origin, and the graph will extend infinitely upwards as ( x ) moves away from zero.
y=x^2
Flipping the graph of the function ( y = x^2 + 2x - 2 ) vertically involves multiplying the entire function by -1. This results in the new equation ( y = -(x^2 + 2x - 2) ), which can be simplified to ( y = -x^2 - 2x + 2 ). So, yes, the flipped graph can be represented as ( y = -(x^2 + 2x - 2) ).
4xy + x3y + yx2 + yx + 3yx = x3y + x2y + 8xy = (xy)(x2y + x + 8)
No, but any parabola can be transformed into the form y = x^2.
If you mean: y = x^2 -6x +6 then the vertex is at (3, -3)
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If you're looking to factor it, you can do it like so: d2ydx2 - yx2 = d3yx2 - yx2 = yx2(d3 - 1)
y=x^2
4xy + x3y + yx2 + yx + 3yx = x3y + x2y + 8xy = (xy)(x2y + x + 8)
upward
There can be no answer because there is no equation of inequality, simply an expression.
y - x = 2 y= -2x + 1
12 x 5 = 60
y=x2-6x+9
No, but any parabola can be transformed into the form y = x^2.
If you mean: y = x^2 -6x +6 then the vertex is at (3, -3)