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y=x^2
4xy + x3y + yx2 + yx + 3yx = x3y + x2y + 8xy = (xy)(x2y + x + 8)
No, but any parabola can be transformed into the form y = x^2.
If you mean: y = x^2 -6x +6 then the vertex is at (3, -3)
"y x 2 2x -3 is not any kind of equation because it does not have an equals sign (=).