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Need help with working this Trig problem out. A sin alpha plus cos alpha equals 1 B sin alpha - cos alpha equals 1 Solution is AB equals 1?
A*sin(x) + cos(x) = 1B*sin(x) - cos(x) = 1Add the two equations: A*sin(x) + B*sin(x) = 2(A+B)*sin(x) = 2sin(x) = 2/(A+B)x = arcsin{2/(A+B)}That is the main solution. There may be others: depending on the range for x.
Solve the right triangle with A equals 52 degrees 15' and a equals 6.7808?
Angle A = 52° 15' = 52 25° therefore angle B = 90 - 52.25 = 37.75°. Using the Sine Rule : a/sin A = b/sin B. 6.7808/sin 52.25 = b/sin 37.75 : b = 6.7808 sin 37.75 ÷ sin 52.25 = 5.2503 Either using the Sine Rule or Pythagoras gives the length of the hypotenuse as 8.5758
What does b plus 24 equals 19 equal?
If the question is, "What is b if b + 24 = 19 ?", then : b + 24 = 19 b = 19 - 24 = -5
A plus b equals 40 b plus c equals 34 a plus c equals 42 b equals?
b = 40 - a, c = 42 - a so b + c = 40 - a + 42 - a, ie 82 -2a = 34 so a = 48/2 ie 24 b = 40 - 24 ie 16 and c = 42 - 24 ie 18
Is a to the b power equals to b to a power?
Example: 24 = 42
