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However, if the equation is y = x^2 + 3 then it is a function.
"y x 2 2x -3 is not any kind of equation because it does not have an equals sign (=).
If you mean: y = x^2 -6x +6 then the vertex is at (3, -3)
помогите плиз сократить дробь 3y^2-8y-6/4-9y^2
The equation x=c where c is a constant is the equation of a vertical line. It can't be a function but it is linear so the answer is no. For example, the vertical line produced by the linear equation x = 3 does not represent a function. We cannot write this equation so that y is a function of x because the only x-value is 3 and this "maps" to every real-number y.
The function or equation is required to solve this.
"y x 2 2x -3 is not any kind of equation because it does not have an equals sign (=).
There can be no answer because there is no equation of inequality, simply an expression.
upward
12 x 5 = 60
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y=x2-6x+9
y - x = 2 y= -2x + 1
You can tell if an equation is a function if for any x value that you put into the function, you get only one y value. The equation you asked about is the equation of a line. It is a function.
Without an equality sign the given terms of an expression can't be considered to be an equation and so therefore no solution is possible.
If you're looking to factor it, you can do it like so: d2ydx2 - yx2 = d3yx2 - yx2 = yx2(d3 - 1)
If you mean: y = x^2 -6x +6 then the vertex is at (3, -3)
If you mean: y = x^2 -6x +6 then the vertex is at (3, -3)